关于括号合规这个函数怎么写

Question

判断一个字符串s，s仅为三种括号，判断括号的使用是否合规，输出True，Flase
题目来自codewars。

"(){}[]"   =>  True
"([{}])"   =>  True
"(}"       =>  False
"[(])"     =>  False
"[({})](]" =>  False
"[({})][]" =>  True
"[({})()][]" =>  True

Answer 1

def validBraces(s):
  while '{}' in s or '()' in s or '[]' in s:
      s=s.replace('{}','')
      s=s.replace('[]','')
      s=s.replace('()','')
  return s==''