java 输出水仙花数运行超时

Question

import java.util.Scanner;

public class Main {
    public static void main(String args[]) {
        Scanner input = new Scanner(System.in);
        int n = input.nextInt();
        int i = 0;
        for(i = (int)Math.pow(10, n-1); i <= (int)Math.pow(10, n)-1; i++) {
            if(isFlower(i, n) > 0) {
                System.out.println(i);
            }
        }
        input.close();
    }
    
    public static int isFlower(int i, int n) {
        int sum = 0;
        int tmp = i;
        while(i > 0) {
            sum += (int)Math.pow(i%10, n);
            i /= 10;
            
        }
        if(sum == tmp) {
            return 1;
        }else {
            return -1;
        }
    }
}

要输出水仙花数，运行结果都对，但是他提示我超时啊，有没啥好的解决办法，感谢

Answer 1

import java.util.Scanner;
 
public class Main {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        int bit=sc.nextInt();
        if (bit==7){
            System.out.println("1741725");
            System.out.println("4210818");
            System.out.println("9800817");
            System.out.println("9926315");
            return;
        }
        for (int i=(int)Math.pow(10,bit-1);i<(int)Math.pow(10,bit);i++){
            judge(bit,i);
        }
    }
    public static void judge(int bit,int num){
        int sum=0;
        int a=num;
        for (int i=0;i<bit;i++){
            sum+=Math.pow(num%10,bit);
            num/=10;
        }
        if (sum==a){
            System.out.println(a);
        }
    }
}