if句输出结果有问题，求修改下

Question

case2的if句我不管输入什么这里输出都是all is true, you can log in和error，没有进行判断。主要出现在第二次logon，然后再login就无法判断了。

Answer 1

import java.util.Scanner;
public class Test {
    public static void main(String[] args){
        String[]usersname=new String[50];
        String[]passwords=new String[50];
        String[]phonenumber=new String[50];
        Scanner input =new Scanner(System.in);
        for1:for(int n=0;n<50;n++){
            System.out.println("enter a number: ");
            System.out.println("1.logon");
            System.out.println("2.login");
            System.out.println("3.forget");
            System.out.println("4.exit");
            int situation=input.nextInt();
            switch (situation) {
                case 1:
                    System.out.println("input your name:");
                    String name=input.next();
                    System.out.println("input your passwords:");
                    String words=input.next();
                    System.out.println("input your phone numbers:");
                    String numbers=input.next();
                    usersname[n]=name;
                    passwords[n]=words;
                    phonenumber[0]=numbers;
                    continue for1;
                case 2:
                    System.out.println("input your name:");
                    String name1=input.next();
                    System.out.println("input your passwords:");
                    String words1=input.next();
                    boolean flag=false;
                    for(int i=0;i<50;i++){
                        if(usersname[i].equals(name1) && passwords[i].equals(words1)){
                            flag=true;
                            break;
                        }
                    if (flag){
                        System.out.println("all is true, you can log in.");
                    }else{
                        System.out.println("error");
                    }
                    }
                    continue for1;
                case 3:
                case 4:
                    break for1;
                default:
                    System.out.println("error");
            }
        }
    }
}