想知道怎么才能变成空心的漏斗

Question

int n;
    cin >> n;
    for (int i = 1;i <= n / 2;i++)
    {
        for (int j = 1;j <= i - 1;j++)
        {
            cout << " ";
        }
        for (int j = 1;j <= n - 2 * (i - 1);j++)
        {
            cout << "*";
        }
        cout << endl;
    }
    for (int i = 1;i <= n / 2 + 1;i++)
    {
        for (int j = 1;j <= (n-(2*i-1))/2 ;j++)
        {
            cout << " ";
        }
        for (int j = 1;j <= 2 * i - 1;j++)
        {
            cout << "*";
        }
        cout << endl;
    }

Answer 1

#include<iostream>
using namespace std;
main(){
 
int n;
    cin >> n;
    for (int i = 0;i < n;i++)
    {
        for (int j = 0;j <n;j++)
        {
            if(i==0||i==n-1)cout << "*";
            else if(j!=i&&j!=n-i-1)cout << " ";
            else cout << "*";
        }
        
        cout << endl;
    }
   
}