C++：为什么这里需要使用引用？ofs.write((const char *)&m1, sizeof(Maker));

Question

如题，为什么在ofs.write和ifs.read的时候需要添加引用？

如果没有引用的话编译器报错：
Error (active) no suitable conversion function from "Maker" to "const char *" exist
按照编译器报的错，加了引用就有转换的函数了?

#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <fstream>
using namespace std;

class Maker {
public:
    Maker() = default;
    Maker(const char * name,int age) {
        strcpy(this->name, name);
        this->age = age;
    }
    void printM() {
        cout<<this->age<<" " << this->name<< endl;
    }
public:
    char name[64];
    int age;
};
int main()
{
    Maker m1("小林", 20);
    Maker m2("布林", 22);
    ofstream ofs;
    ofs.open("test.dat", ios::out |ios::binary );
    if (!ofs.is_open()) {
        cout << "打开文件失败" << endl;
    } 
    ofs.write((const char *)&m1, sizeof(Maker));//这里强制类型转换，会产生临时量
    ofs.write((const char *)&m2, sizeof(Maker));
    ofs.close();
    ifstream ifs;
    ifs.open("test.dat", ios::in | ios::binary);
    if (!ifs.is_open()) {
        cout << "dakaiwenjianshibai" << endl;
    }
    Maker m3;
    Maker m4;
    ifs.read((char*)&m3, sizeof(Maker));
    ifs.read((char*)&m4, sizeof(Maker));
    m3.printM();
    m4.printM();
    system("pause");
    return 0;
}

Answer 1

晕，这不是引用啊，这是取地址符啊。就是取m1的地址，然后转换成const char*指针
&只有在定义变量的时候才是引用的意思