用c语音简单进行四则运算

Question

Answer 1

#include<stdio.h>
int main()
{
  int a=0,b=0,sum=0;
  char c;
  scanf("%d%c%d",&a,&c,&b);
  if(c == '+')
  {
    sum = a + b;
    printf("%d+%d=%d",a,b,sum);
  }
  else if(c == '-')
  {
    sum = a - b;
    printf("%d-%d=%d",a,b,sum);
  }
  else if(c == '*')
  {
    sum = a * b;
    printf("%d*%d=%d",a,b,sum);
  }
  else if(c == '/')
  {
    if(a == 0)return -1;
    else
    {
      sum = a / b;
      printf("%d/%d=%d",a,b,sum);
    }
  }
  else if(c == '%')
  {
    if(a == 0)return -1;
    else
    {
      sum = a % b;
      printf("%d%%d=%d",a,b,sum);
    }
  }
  return 0;
}