Python程序大学课程写程序

Question

定义一个函数，实现两个字典(所有value都为数值型)的相加，不同的key对应的值保留，相同的key对应的值相加后保留。如:

dict_ a={"a":1, "b":2, "c":3, "d":4}

dict_ b= {"b":3, "d":5, "e":7, "m":9}

结果为:

dict_ c= {"a":1, "b":5, "c":3, "d":9, "e":7, "m":9}

Answer 1

dict_a = {"a": 1, "b": 2, "c": 3, "d": 4}
dict_b = {"b": 3, "d": 5, "e": 7, "m": 9}
dict_c = dict_a
for k, v in dict_b.items():
    if dict_c.get(k):
        dict_c[k] += v
    else:
        dict_c[k] = v
print(dict_c)

有帮助请采纳,有问题继续交流,你的采纳是对我回答的最大的肯定和动力