nginx+jquery+fastcgi+django，getJSON请求无法读取返回值，报An unhandled exception was thrown by the application

Question

如题。浏览器上看到返回码是200，但返回值报：Unhandled Exception
An unhandled exception was thrown by the application.
折腾了一天了，死活没法把django里的值取到。求指导！

1、jquery中的相关代码如下：
$.getJSON("/server/authorize/islogin", function(result){
if(result.res == -1){
window.location.href = "/pages/login.html";
}
……
2、DJANGO中的结构是：项目名叫MMP，上面islogin所在的app叫authorize
/server/MMP/MMP文件夹里的urls.py相关代码如下：
urlpatterns = [
url(r'^authorize/', include('authorize.urls')),
]))
]
/server/MMP/authorize文件夹里的urls.py相关代码如下：
from views import auth_islogin,auth_login,auth_test,auth_logout,auth_chpwd
urlpatterns = [
url(r'^islogin/$',auth_islogin),
]
views.py相关代码如下：
def auth_islogin(request):
resx = {'res':-1}
return HttpResponse(json.dumps(resx),content_type="application/json")
3、我是windows操作系统，nginx.conf中fastcgi的相关配置如下：

        location /server/
        {
            fastcgi_pass 127.0.0.1:8051;
            fastcgi_param PATH_INFO $fastcgi_script_name;
            fastcgi_param REQUEST_METHOD $request_method;
            fastcgi_param QUERY_STRING $query_string;
            fastcgi_param CONTENT_TYPE $content_type;
            fastcgi_param CONTENT_LENGTH $content_length;
            fastcgi_param SERVER_PROTOCOL $server_protocol;
            fastcgi_param SERVER_PORT $server_port;
            fastcgi_param SERVER_NAME $server_name;
            #fastcgi_pass_header Authorization;
        fastcgi_param REQUEST_URI $document_uri;
            fastcgi_param DOCUMENT_ROOT $document_root;
        fastcgi_param SERVER_ADDR $server_addr;
        fastcgi_param REMOTE_USER $remote_user;
        fastcgi_param REMOTE_ADDR $remote_user;
        fastcgi_param REMOTE_PORT $remote_port;
        fastcgi_param SERVER_SOFTWARE "nginx";
        fastcgi_param GATEWAY_INTERFACE "CGI/1.1";
        #fastcgi_param GEO $geo;
        fastcgi_param UID_SET $uid_set;
        fastcgi_param UID_GOT $uid_got;
            fastcgi_intercept_errors off;
        access_log nginx_django.log;
        }

Answer 1

你可以在js里console.log(result)，看看result是什么内容。