数组编写矩阵对角线..

Question

#include<stdio.h>
int main()
{
int i,j,a[5][5],s1=0,s2=0,s3=0;
printf("Input the matrix(5*5):\n");
for(i=0;i<5;i++){
for(j=0;j<5;j++){
scanf("%d",&a[i][j]);
}
}
for(i=0;i<5;i++){
for(j=0;j<5;j++){
s1=s1+a[i][j];
break;
}
}
for(i=0;i<5;i++){
for(j=4;j>=0;j--){
s2=s2+a[i][j];
break;
}
}
s3=s1+s2;
printf("s1=%d,s2=%d,s3=%d",s1,s2,s3);
return 0;
}

Answer 1

#include<stdio.h>
int main() {
    int i, j, a[5][5], s1 = 0, s2 = 0, s3 = 0;
    printf("Input the matrix(5*5):\n");
    for(i = 0; i < 5; i++) {
        for(j = 0; j < 5; j++) {
            scanf("%d", &a[i][j]);
        }
    }
    for(i = 0; i < 5; i++) {
        for(j = 0; j < 5; j++) {
            if(i == j)
                s1 = s1 + a[i][j];
            if(i + j == 4)
                s2 = s2 + a[i][j];
            if(i == 0 || i == 4 || j == 0 || j == 4)
                s3 = s3 + a[i][j];
        }
    }
    printf("s1=%d,s2=%d,s3=%d", s1, s2, s3);
    return 0;
}