u010493679 2021-12-03 16:02 采纳率: 95.7%
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已结题

for循环得到的结果,怎么输出到一个列表?

请问,
1、可以将案例的结果,(有数字重复,论坛不让发,麻烦运行下)
输出到一个列表中吗(【”55.81 50.62 3 3,“61.35 50.62 19 3”,等等】)
2、代码有能优化的地方吗

l=[[54.47, 50.62], [55.81, 53.84], [55.27, 53.7], [54.42, 53.72], [57.56, 53.18], [59.24, 57.34], [59.53, 57.57], [59.53, 59.53], [63.49, 60.44], [62.96, 61.160000000000004], [62.04, 60.55], [61.35, 59.57], [59.81, 57.52], [60.6, 59.01], [59.32, 58.52], [59.82, 58.4], [59.77, 58.43], [60.87, 59.03], [61.32, 58.73], [59.37, 58.51], [60.2, 58.38], [60.21, 59.410000000000004], [62.39, 59.83], [61.82, 60.96], [60.95, 58.62], [59.77, 58.22], [60.3, 59.29], [60.25, 59.410000000000004], [60.22, 58.4], [58.69, 57.54], [58.22, 56.87], [57.73, 56.42], [60.48, 56.73], [59.3, 58.36], [59.61, 58.32], [58.7, 57.9], [59.3, 56.910000000000004], [61.13, 58.52], [63.01, 59.15], [59.81, 58.9], [61.19, 58.39], [59.95, 59.32], [60.93, 59.43], [60.89, 60.22], [62.0, 59.52], [60.73, 59.62], [60.17, 59.02], [59.69, 58.92], [59.57, 57.69], [59.24, 58.04], [59.07, 58.37], [59.12, 58.19], [59.58, 58.37], [61.17, 59.27], [60.69, 59.32], [60.2, 59.45], [61.17, 59.34], [61.99, 60.46], [61.77, 60.3], [61.49, 60.410000000000004], [61.4, 58.49], [61.25, 59.71], [61.69, 60.52], [61.18, 60.48], [60.57, 58.48], [59.99, 57.86], [58.82, 57.82], [60.27, 58.53], [60.2, 58.69], [60.08, 59.31]]

weizhi = 0
high = l[0][0]
low = l[0][1]
num = 0
for i in range(len(l)):
    if l[i+weizhi][0] >= high and l[i+weizhi][1] > low:
        if num >=3:
            high = l[i+weizhi][0]
            low= low
            num1 = num
            print(high,low,i+weizhi,num,1,num1)
            break
        num = 0
        high = l[i+weizhi][0]
        low= low 
        weizhi = weizhi+i
    if l[i+weizhi][0] >= high and l[i+weizhi][1] <= low:
        if num >=3:
            high = l[i+weizhi][0]
            low= l[i+weizhi][1]
            print(high,low,i+weizhi,2)
            break
        num = 0
        high = l[i+weizhi][0]
        low= l[i+weizhi][1]
        weizhi = weizhi+i
    if l[i+weizhi][0] < high and l[i+weizhi][1] >= low:
        high = high
        low= low
        num = num+1
        weizhi = weizhi+i
        print(high,low,i+weizhi,3)
    if l[i+weizhi][0] <= high and l[i+weizhi][1] <= low:
        if num >=3:
            high = l[i+weizhi][0]
            low= l[i+weizhi][1]
            print(high,low,i+weizhi,4)
            break
        num = 0
        high = l[i+weizhi][0]
        low= l[i+weizhi][1]
        weizhi = weizhi+i
weizhi =weizhi
high = high
low = low
num = 0

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  • 系统已结题 12月11日
  • 已采纳回答 12月3日
  • 修改了问题 12月3日
  • 创建了问题 12月3日

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