使用ObjectMapper对象将json转化为对象的时候运行之后是这个，怎么搞的

Question

{"resultcode":"200","reason":"Return Successd!","result":{"province":"江苏","city":"淮安","areacode":"0517","zip":"223001","company":"电信","card":""},"error_code":0}
Exception in thread "main" com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "resultcode" (class pojo.Pespon), not marked as ignorable (3 known properties: "reason", "result", "error_code"])
at [Source: (String)"{"resultcode":"200","reason":"Return Successd!","result":{"province":"江苏","city":"淮安","areacode":"0517","zip":"223001","company":"电信","card":""},"error_code":0}"; line: 1, column: 16] (through reference chain: pojo.Pespon["resultcode"])
at com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:61)
at com.fasterxml.jackson.databind.DeserializationContext.handleUnknownProperty(DeserializationContext.java:840)
at com.fasterxml.jackson.databind.deser.std.StdDeserializer.handleUnknownProperty(StdDeserializer.java:1206)
at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownProperty(BeanDeserializerBase.java:1592)
at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownVanilla(BeanDeserializerBase.java:1570)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.vanillaDeserialize(BeanDeserializer.java:294)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:151)
at com.fasterxml.jackson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:4202)
at com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:3205)
at com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:3173)
at phone.Phonetest.main(Phonetest.java:37)

Answer 1

完整代码发一下
Unrecognized field "resultcode"
无法识别这个resultcode 属性