下列程序运行结果为什么是4

Question

#include <stdio.h>void main()
{int a=1,b;for(b=1;b<=10;b++)
{ if(a>=8)break;if(a%2==1){a+=5;
continue;}a=3; }printf("%d\n",b);
}

Answer 1

a = 1,b = 1, a % 2 == 1, a+= 5,a = 6, continue
a = 6, b = 2, a % 2 != 1,a = 3
a = 3, b = 3, a % 2 == 1, a+= 5,a = 8,continue
a = 8, b = 4, a >= 8, break退出循环
此时b = 4