c语言，输出链表无输出值

Question

#include<stdio.h>
#include<stdlib.h>
struct demo
{
    char str[15];
    struct damo* pnext;
};
struct demo* create()
{
    struct demo* pnew,*pend,*phead;
    pnew=pend=(struct demo*)malloc(sizeof(struct demo));
    phead=pnew;
    printf("请输入文字");
    scanf("%s",phead->str);
    if(*(phead->str)!="\n");
    {
        for(;;)
        {
            pnew=(struct demo*)malloc(sizeof(struct demo));
            pend->pnext=pnew;
            printf("请输入文字");
            scanf("%s",pnew->str);
            if(*(pend->str)=="\n")
            {
                break;
            }
            pend=pnew;
        }
    }
    pend->pnext=NULL;
    return phead;
}
void main()
{
    struct demo* phead;
    struct demo* pprint;
    phead=create();
    printf("\n输出为：\n");
    pprint=phead;
    printf("%s",*(pprint->str));
    for(;;)
    {
        pprint=pprint->pnext;
        printf("%s",*(pprint->str));
        if(pprint==NULL)
        {
            break;
        }
        
    }
    
}

链表可以正常输入，但是当输入回车退出输入的循环后，就无法正常输出了，求解答，谢谢

Answer 1

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

struct demo
{
    char str[15];
    struct demo *next;
};

struct demo *create()
{
    struct demo *head = NULL;
    struct demo *tail = NULL;
    char buffer[15];
    while (scanf("%s", buffer) == 1) // Read input till EOF (i.e. Ctrl+D (Linux) / Ctrl+Z (Windows))
    {
        struct demo *p = (struct demo *)malloc(sizeof(struct demo));
        strcpy(p->str, buffer);
        p->next = NULL;
        if (!head)
            head = p;
        if (tail)
            tail->next = p;
        tail = p;
    }
    return head;
}

void print(struct demo *head)
{
    while (head)
    {
        printf("%s\n", head->str);
        head = head->next;
    }
}

void destroy(struct demo *head)
{
    while (head)
    {
        struct demo *p = head;
        head = head->next;
        free(p);
    }
}

int main()
{
    struct demo *head = create();
    print(head);
    destroy(head);
}