jieba分词后，想要对分词进行词频统计和排序，使用print函数输出的是分词遍历的结果

Question

jieba分词后，想要对分词进行词频统计和排序，使用print函数输出的是分词遍历的结果。

def chinese_word_cut(mytext):

jieba.load_userdict(dic_file)
jieba.initialize()
try:
    stopword_list = open(stop_file, encoding='utf-8')
except:
    stopword_list = []
    print("error in stop_file")
stop_list = []
flag_list = ['n', 'nz', 'vn']
for line in stopword_list:
    line = re.sub(u'\n|\\r', '', line)
    stop_list.append(line)

   # jieba分词
   seg_list = psg.cut(mytext)
    word_list = []
    word_freq = {}
    count_dict = dict()
    for seg_word in seg_list:
        # word = re.sub(u'[^\u4e00-\u9fa5]','',seg_word.word)
        word = seg_word.word
        find = 0
        for stop_word in stop_list:
            if stop_word == word or len(word) < 2:  # this word is stopword
                find = 1
                break
        if find == 0 and seg_word.flag in flag_list:
            for word in word_list:
                if word in word_freq:
                    count_dict[word] += 1
                else:
                    count_dict[word] = 1
            word_list.append(word)
        print(sorted(count_dict.items(),key=lambda x:x[1],reverse=True))

运行显示的是分词遍历的结果：[('文化', 1)] [('标准', 1)] [('印发', 1)]

我尝试过把for word in word_freq 等循环语句放在不同的位置，但是显示结果都是分词的遍历

想要最终显示出[(key,value)],value是key的总计值，而非是“1”。

Answer 1

h_txt = getText()
words = h_txt.split()
counts = {}
for word in words:
    counts[word] = counts.get(word, 0) + 1
items = list(counts.items())
items.sort(key=lambda x: x[1], reverse=True)
for i in range(10):
    s = items[i]
    print(s)