本人正在练习通过selenium爬取上市公司年报,试了很久才写出如下效果,但其中的selenium定位语句,实在不知道怎么优化,试了很多次,每次都报错,所以期待有高人可以拨冗指点,谢谢!
```python
import re
from selenium import webdriver
from selenium.webdriver import ActionChains
from selenium.webdriver.chrome.options import Options
import requests
def main( out_fold ):
url = "https://gu.qq.com/sh600018/gp/jbnb/"
file_list = {}
chrome_options = Options()
chrome_options.add_argument('--log-level=3')
chrome_options.add_argument('--disable-gpu') # 禁用gpu
chrome_options.add_argument('--mute-audio') # 关闭声音
driver = webdriver.Chrome(options=chrome_options, executable_path=r"E:/python_work/BrowseDriver/chromedriver.exe")
driver.implicitly_wait(2)
driver.get(url)
ul = driver.find_element_by_xpath("//strong[text()='公告标题']/../..") # 这块怎么一次性取到报告区域呢???
lis = ul.find_elements_by_xpath('./*') # 每行报告记录
for index, li in enumerate(lis):
eles = li.find_elements_by_xpath('./*')
filename = eles[0].text
file_list[ index ] = {
"filename" : filename ,
"href" : eles[0].get_attribute("href")
}
for k in file_list: # 遍历存储的 file_list
if file_list[k]['filename'] =="公告标题":
continue
driver.implicitly_wait(2)
driver.get( file_list[k]['href'] )
ele = driver.find_element_by_xpath("//a[@class='yk_on']/../..") # 这块语句怎么优化,始终无法直接读取到iframe?????
ele1 = ele.find_elements_by_xpath('./*')
ele2 = ele1[2].find_elements_by_xpath('./*')
ele3 = ele2[0].find_elements_by_xpath('./*')
pdf_src = ele3[1].get_attribute("src")
r = requests.get( pdf_src )
filename_full_path = out_fold + file_list[k]['filename'] + ".pdf"
with open( filename_full_path , "wb") as f:
f.write(r.content)
print("over")
if __name__ == '__main__':
out_fold = 'D:\\data_work\\财报分析模型\财报\\tt\\'
main( out_fold )
```