输入n个数,求其中最大值,最小值,和小于平均数的个数
#include<stdio.h>
int main()
{
int i,n,max,min,count=0,sum=0,a[i];
double average;
scanf("%d",&n);
for(i=0;i<n;i++){
scanf("%d",a[i]);
sum=sum+a[i];
}
average=sum/n;
for(i=0;i<n;i++){
if(a[i]<average){
count++;
}
a[0]=min;
if(a[i]>min){
a[i]=min;
}
a[0]=max;
if(a[i]<max){
a[i]=max;
}
}
printf("max=%d,min=%d,average=%.2f,count=%d",max,min,average,count);
return 0;
}