利用c/c++创建复数二维数组，也就是复数矩阵，同时把matlab生成的复数矩阵保存为txt格式的数据读入c/c++的复数矩阵里。

Question

利用c/c++创建复数二维数组，也就是复数矩阵，同时把matlab生成的复数矩阵保存为txt格式的数据读入c/c++的复数矩阵里。
希望能够说的详细一点点，实在看不懂网络上的各种教程

Answer 1

1、先写matlab导出的

A=[1,3;2,4;0,2]-[5,8;6,9;1,3]*i;
dlmwrite('C:\\Users\\Lenovo\\Desktop\\1.txt', A);

效果：

2、c++

其实它有定义，但是我不太了解，直接用自定义的

#include<iostream>
#include<fstream>    
#include <string>
#include<vector>
using namespace std;

//自定义复数类
class CPLX {
public:
    double r, i;
    CPLX(double rr = 0, double ii = 0) :r(rr), i(ii) {

    }
    friend istream& operator>>(istream& is, CPLX& C) {
        char tmp = '\0',top='\0';
        top = is.peek();
        double a, b;
        if (top == '+' || top == '-' || (int('0') <= (int)top && (int)top <= int('9'))) {
            is >> a;
            top = is.peek();
            if (top == 'I' || top == 'i') {//bi
                C.i = a; C.r = 0;
                is >> tmp;
                return is;
            }
            else if (top == '+' || top == '-') {
                is >> b;
                top = is.peek();
                if (top == 'I' || top == 'i') {//a+/-bi
                    C.r = a, C.i = b;
                    is >> tmp; 
                    return is;
                }
            }
            else {//a
                C.r = a; C.i = 0; 
                return is;
            }
        }
        //剩下的全是不符合格式的，抛异常处理
        throw  invalid_argument("输入的复数格式不正确，应该为[a+bi,a-bi,a,bi]");
        is.fail();
        return is;
    }
    friend ostream& operator<<(ostream& os, const CPLX& c) {
        if (c.i == 0.0)
            os << std::noshowpos<< c.r;
        else if (c.r == 0.0) {
            if (c.i == 1)
                os << 'i';
            else  if (c.i == -1)
                os << '-' << 'i';
            else
                 os << c.i << 'i';
        }           
        else
            os << std::noshowpos << c.r << std::showpos << c.i<< 'i';
        return os;
    }
};

int main()
{
    CPLX tmpCP;
    vector<vector<CPLX>>source;
    const char* path = "C:\\Users\\Lenovo\\Desktop\\1.txt";
    ifstream myfile(path);
    if (!myfile.is_open())
    {
        cout << "未成功打开文件" << endl;
    }
    char tmpStr = '\0';
    int i = 0;
    source.push_back(vector<CPLX>());
    while (myfile >> tmpCP) {
        source[i].push_back(tmpCP);
        tmpStr = myfile.peek();
        if (tmpStr != ',' && tmpStr != EOF) {//不在同一行
            i += 1;
            source.push_back(vector<CPLX>());
            myfile.get(tmpStr);
            if (myfile.peek() == EOF)//判断是否读取到文件最后
                break;
        }
        else if(tmpStr == EOF)//判断是否读取到文件最后
            break;
        else {
            myfile >> tmpStr;
        }
       
    }
    if (source[i].size() == 0)
        source.pop_back();
    myfile.close();
    int w = 0, h = 0, H = 0;
    for (auto iter = source.begin(); iter != source.end(); ++iter) {//遍历行
        h = 0;
        for (int i = 0; i < (*iter).size(); ++i) {//遍历列
            cout << (*iter)[i] << " ";
            h += 1;
        }
        if (H != 0 && h != H)
            throw  invalid_argument("要串联的数组的维度不一致。");
        else
            H = h;
        w += 1;
        cout << endl;
    }
    cout << "shape=(" << std::noshowpos<<w << "," << H << ")" << endl;
}