怎么把结构化数组转为普通数组

Question

A = [[array(['10:30'], dtype='<U5')]
 [array(['13:12'], dtype='<U5')]
 [array(['14:56'], dtype='<U5')]
 ...
 [array(['15:00'], dtype='<U5')]
 [array(['15:01'], dtype='<U5')]
 [array(['15:02'], dtype='<U5')]]

怎么把数组A转化为B这个样子啊 B中元素type为时间

B = [10:30，13:12，14:56，...，15:00，15:01，15:02]

Answer 1

>>>import numpy as np
>>>A = [[np.array(['10:30'], dtype='<U5')],
 [np.array(['13:12'], dtype='<U5')],
 [np.array(['14:56'], dtype='<U5')],
 [np.array(['15:00'], dtype='<U5')],
 [np.array(['15:01'], dtype='<U5')],
 [np.array(['15:02'], dtype='<U5')]]
>>> B = [A[i][0][0] for i in range(len(A))]
>>> print(B)
['10:30', '13:12', '14:56', '15:00', '15:01', '15:02']