Python：石头剪刀布游戏的分析

Question

缺失一段代码，可否有人填一下

# -*- coding:utf-8 -*-
import random
people_guess = [ x for x in map( str, input("").split(",") ) ]
guess_list = ["石头","剪刀","剪刀","布","布","石头","布"] # 电脑出拳的方式
computer_win_condition = [["布","石头"],["石头","剪刀"],["剪刀","布"]] # 每次电脑赢的情况
balance_condition = [["布","布"],["石头","石头"],["剪刀","剪刀"]] # 每次平局的情况
computer_win_number = 0 # 电脑赢的次数
people_win_number = 0   # 玩家赢得次数

#********* Begin *********#
 # 在此处补全代码
#********* End *********#

# 游戏进行 7 次之后，进行输赢的判别
if computer_win_number > people_win_number:
    print("电脑赢!",end="")
elif computer_win_number < people_win_number:
    print( "玩家赢!", end="" )
else:
    print("平局!")

Answer 1

if len(guess_list) < len(people_guess):
    print("次数不足，请输入{}次出拳".format(len(guess_list)))
    exit(1)
for i in range(len(guess_list)):

    if [guess_list[i],people_guess[i]] in computer_win_condition:
        computer_win_number += 1
    elif [guess_list[i],people_guess[i]] in balance_condition:
        continue
    else:
        people_win_number += 1