uni-app音频全局播放功能思路 5C

2个回答

6 个月之前 回复
grhrhr5 回复心想））事成: 卧槽，楼主找到方法没，我也是同样问题，只要切换了页面就断了音乐播放，息屏之后还不能自动播放下一首
6 个月之前 回复

7 个月之前 回复

uni-app中查找main.css文件查找不见,路径正确,

uni-app怎么选中一段文本并弹出一个自己定义的搜索、复制悬浮框，并给选中文字划线。

Multi-bit Trie 程序的思想
Problem Description 　　IP lookup is one of the key functions of routers for packets forwarding and classifying. Generally, IP lookup can be simplified as a Longest Prefix Matching (LPM) problem. That's to find the longest prefix in the Forwarding Information Base (FIB) that matches the input packet's destination address, and then output the corresponding Next Hop information. 　　Trie-based solution is the most wildly used one to solve LPM. As shown in Fig.1(b), an uni-bit trie is just a binary tree. Processing LPM on it needs only traversing it from the root to some leaf, according to the input packet's destination address. The longest prefix along this traversing path is the matched one. In order to reduce the memory accesses for one lookup, we can compress some consecutively levels of the Uni-bit Trie into one level, transforming the Uni-bit Trie into a Multi-bit Trie. 　　For example, suppose the strides array is {3, 2, 1, 1}, then we can transform the Uni-bit Trie shown in Fig.1(b) into a Multi-bit Trie as shown in Fig.1(c). During the transforming process, some prefixes must be expanded. Such as 11(P2), since the first stride is 3, it should be expanded to 110(P2) and 111(P2). But 110(P5) is already exist in the FIB, so we only store the longer one 110(P5). 　　Multi-bit Trie can obviously reduce the tree level, but the problem is how to build a Multi-bit Trie with the minimal memory consumption (the number of memory units). As shown in Fig.1, the Uni-bit Trie has 23 nodes and consumes 46 memory units in total, while the Multi-bit Trie has 12 nodes and consumes 38 memory units in total. Input 　　The first line is an integer T, which is the number of testing cases. 　　The first line of each case contains one integer L, which means the number of levels in the Uni-bit Trie. 　　Following L lines indicate the nodes in each level of the Uni-bit Trie. 　　Since only 64 bits of an IPv6 address is used for forwarding, a Uni-bit Trie has maximal 64 levels. Moreover, we suppose that the stride for each level of a Multi-bit Trie must be less than or equal to 20. Output 　　Output the minimal possible memory units consumed by the corresponding Multi-bit Trie. Sample Input 1 7 1 2 4 4 5 4 3 Sample Output 38
iphone6s 中的video标签
Multi-bit Trie 是怎么编写代码
Problem Description 　　IP lookup is one of the key functions of routers for packets forwarding and classifying. Generally, IP lookup can be simplified as a Longest Prefix Matching (LPM) problem. That's to find the longest prefix in the Forwarding Information Base (FIB) that matches the input packet's destination address, and then output the corresponding Next Hop information. 　　Trie-based solution is the most wildly used one to solve LPM. As shown in Fig.1(b), an uni-bit trie is just a binary tree. Processing LPM on it needs only traversing it from the root to some leaf, according to the input packet's destination address. The longest prefix along this traversing path is the matched one. In order to reduce the memory accesses for one lookup, we can compress some consecutively levels of the Uni-bit Trie into one level, transforming the Uni-bit Trie into a Multi-bit Trie. 　　For example, suppose the strides array is {3, 2, 1, 1}, then we can transform the Uni-bit Trie shown in Fig.1(b) into a Multi-bit Trie as shown in Fig.1(c). During the transforming process, some prefixes must be expanded. Such as 11(P2), since the first stride is 3, it should be expanded to 110(P2) and 111(P2). But 110(P5) is already exist in the FIB, so we only store the longer one 110(P5). 　　Multi-bit Trie can obviously reduce the tree level, but the problem is how to build a Multi-bit Trie with the minimal memory consumption (the number of memory units). As shown in Fig.1, the Uni-bit Trie has 23 nodes and consumes 46 memory units in total, while the Multi-bit Trie has 12 nodes and consumes 38 memory units in total. Input 　　The first line is an integer T, which is the number of testing cases. 　　The first line of each case contains one integer L, which means the number of levels in the Uni-bit Trie. 　　Following L lines indicate the nodes in each level of the Uni-bit Trie. 　　Since only 64 bits of an IPv6 address is used for forwarding, a Uni-bit Trie has maximal 64 levels. Moreover, we suppose that the stride for each level of a Multi-bit Trie must be less than or equal to 20. Output 　　Output the minimal possible memory units consumed by the corresponding Multi-bit Trie. Sample Input 1 7 1 2 4 4 5 4 3 Sample Output 38
component 动态组件为子组件， props获取不到数据
Multi-bit Trie
Problem Description 　　IP lookup is one of the key functions of routers for packets forwarding and classifying. Generally, IP lookup can be simplified as a Longest Prefix Matching (LPM) problem. That's to find the longest prefix in the Forwarding Information Base (FIB) that matches the input packet's destination address, and then output the corresponding Next Hop information. ![](http://acm.hdu.edu.cn/data/images/C468-1006-1.jpg) 　　Trie-based solution is the most wildly used one to solve LPM. As shown in Fig.1(b), an uni-bit trie is just a binary tree. Processing LPM on it needs only traversing it from the root to some leaf, according to the input packet's destination address. The longest prefix along this traversing path is the matched one. In order to reduce the memory accesses for one lookup, we can compress some consecutively levels of the Uni-bit Trie into one level, transforming the Uni-bit Trie into a Multi-bit Trie. 　　For example, suppose the strides array is {3, 2, 1, 1}, then we can transform the Uni-bit Trie shown in Fig.1(b) into a Multi-bit Trie as shown in Fig.1(c). During the transforming process, some prefixes must be expanded. Such as 11(P2), since the first stride is 3, it should be expanded to 110(P2) and 111(P2). But 110(P5) is already exist in the FIB, so we only store the longer one 110(P5). 　　Multi-bit Trie can obviously reduce the tree level, but the problem is how to build a Multi-bit Trie with the minimal memory consumption (the number of memory units). As shown in Fig.1, the Uni-bit Trie has 23 nodes and consumes 46 memory units in total, while the Multi-bit Trie has 12 nodes and consumes 38 memory units in total. Input 　　The first line is an integer T, which is the number of testing cases. 　　The first line of each case contains one integer L, which means the number of levels in the Uni-bit Trie. 　　Following L lines indicate the nodes in each level of the Uni-bit Trie. 　　Since only 64 bits of an IPv6 address is used for forwarding, a Uni-bit Trie has maximal 64 levels. Moreover, we suppose that the stride for each level of a Multi-bit Trie must be less than or equal to 20. Output 　　Output the minimal possible memory units consumed by the corresponding Multi-bit Trie. Sample Input 1 7 1 2 4 4 5 4 3 Sample Output 38
uniapp怎么实现轨迹显示

uniapp怎么实现轨迹显示？

Problem Description 　　IP lookup is one of the key functions of routers for packets forwarding and classifying. Generally, IP lookup can be simplified as a Longest Prefix Matching (LPM) problem. That's to find the longest prefix in the Forwarding Information Base (FIB) that matches the input packet's destination address, and then output the corresponding Next Hop information. 　　Trie-based solution is the most wildly used one to solve LPM. As shown in Fig.1(b), an uni-bit trie is just a binary tree. Processing LPM on it needs only traversing it from the root to some leaf, according to the input packet's destination address. The longest prefix along this traversing path is the matched one. In order to reduce the memory accesses for one lookup, we can compress some consecutively levels of the Uni-bit Trie into one level, transforming the Uni-bit Trie into a Multi-bit Trie. 　　For example, suppose the strides array is {3, 2, 1, 1}, then we can transform the Uni-bit Trie shown in Fig.1(b) into a Multi-bit Trie as shown in Fig.1(c). During the transforming process, some prefixes must be expanded. Such as 11(P2), since the first stride is 3, it should be expanded to 110(P2) and 111(P2). But 110(P5) is already exist in the FIB, so we only store the longer one 110(P5). 　　Multi-bit Trie can obviously reduce the tree level, but the problem is how to build a Multi-bit Trie with the minimal memory consumption (the number of memory units). As shown in Fig.1, the Uni-bit Trie has 23 nodes and consumes 46 memory units in total, while the Multi-bit Trie has 12 nodes and consumes 38 memory units in total. Input 　　The first line is an integer T, which is the number of testing cases. 　　The first line of each case contains one integer L, which means the number of levels in the Uni-bit Trie. 　　Following L lines indicate the nodes in each level of the Uni-bit Trie. 　　Since only 64 bits of an IPv6 address is used for forwarding, a Uni-bit Trie has maximal 64 levels. Moreover, we suppose that the stride for each level of a Multi-bit Trie must be less than or equal to 20. Output 　　Output the minimal possible memory units consumed by the corresponding Multi-bit Trie. Sample Input 1 7 1 2 4 4 5 4 3 Sample Output 38
uni.canvasToTempFilePath 图片部分机型会出现空白

ngrx和双向绑定的关系？

redirect_uni参数错误
![图片说明](https://img-ask.csdn.net/upload/201711/14/1510645584_802730.png) 相关代码： public function getOauthUserInfoUrl(\$callback, \$state = '') { return "https://open.weixin.qq.com/connect/oauth2/authorize?appid={\$this->account['key']}&redirect_uri={\$callback}&response_type=code&scope=snsapi_userinfo&state={\$state}#wechat_redirect"; } -------------------------------------------------------------------------------------- \$url = (!empty(\$unisetting['oauth']['host']) ? (\$unisetting['oauth']['host'] . '/') : \$_W['siteroot']) . "app/index.php?i={\$_W['uniacid']}{\$str}&c=auth&a=oauth&scope=userinfo"; \$callback = urlencode(\$url); \$oauth_account = WeAccount::create(\$_W['account']['oauth']); \$forward = \$oauth_account->getOauthUserInfoUrl(\$callback, \$state); header('Location: ' . \$forward); exit;
URLs
In the early nineties, the World Wide Web (WWW) was invented. Nowadays, most people think that the WWW simply consists of all the pretty (or not so pretty) HTML-pages that you can read with your WWW browser. But back then, one of the main intentions behind the design of the WWW was to unify several existing communication protocols. Then (and even now), information on the Internet was available via a multitude of channels: FTP, HTTP, E-Mail, News, Gopher, and many more. Thanks to the WWW, all these services can now be uniformly addressed via URLs (Uniform Resource Locators). The syntax of URLs is defined in the Internet standard RFC 1738. For our problem, we consider a simplified version of the syntax, which is as follows: <protocol> "://" <host> [ ":" <port> ] [ "/" <path> ] The square brackets [] mean that the enclosed string is optional and may or may not appear. Examples of URLs are the following: http://www.informatik.uni-ulm.de/acm ftp://acm.baylor.edu:1234/pub/staff/mr-p gopher://veryold.edu More specifically, <protocol> is always one of http, ftp or gopher. <host> is a string consisting of alphabetic (a-z, A-Z) or numeric (0-9) characters and points (.). <port> is a positive integer, smaller than 65536. <path> is a string that contains no spaces. You are to write a program that parses an URL into its components. Input The input starts with a line containing a single integer n, the number of URLs in the input. The following n lines contain one URL each, in the format described above. The URLs will consist of at most 60 characters each. Output For each URL in the input first print the number of the URL, as shown in the sample output. Then print four lines, stating the protocol, host, port and path specified by the URL. If the port and/or path are not given in the URL, print the string <default> instead. Adhere to the format shown in the sample output. Print a blank line after each test case. Sample Input 3 ftp://acm.baylor.edu:1234/pub/staff/mr-p http://www.informatik.uni-ulm.de/acm gopher://veryold.edu Sample Output URL #1 Protocol = ftp Host = acm.baylor.edu Port = 1234 Path = pub/staff/mr-p URL #2 Protocol = http Host = www.informatik.uni-ulm.de Port = <default> Path = acm URL #3 Protocol = gopher Host = veryold.edu Port = <default> Path = <default>
vue如何将api请求收到的数据动态的显示到模板上呢？

freeswitch对接mod_unimrcp进行ASR语音识别时，unimrcp服务器一直显示检测中，但检测不到语音？
《奇巧淫技》系列-python！！每天早上八点自动发送天气预报邮件到QQ邮箱

Linux(服务器编程):15---两种高效的事件处理模式（reactor模式、proactor模式）

C语言魔塔游戏

​ 进程通信是指进程之间的信息交换。这里需要和进程同步做一下区分，进程同步控制多个进程按一定顺序执行，进程通信是一种手段，而进程同步是目标。从某方面来讲，进程通信可以解决进程同步问题。 ​ 首先回顾下我们前面博文中讲到的信号量机制，为了实现进程的互斥与同步，需要在进程间交换一定的信息，因此信号量机制也可以被归为进程通信的一种方式，但是也被称为低级进程通信，主要原因为： 效率低：一次只可操作少量的...

Python爬虫爬取淘宝，京东商品信息

Java工作4年来应聘要16K最后没要,细节如下。。。

2020年，冯唐49岁：我给20、30岁IT职场年轻人的建议

##1、骇客帝国(1999) 概念：在线/离线，递归，循环，矩阵等 剧情简介： 不久的将来，网络黑客尼奥对这个看似正常的现实世界产生了怀疑。 他结识了黑客崔妮蒂，并见到了黑客组织的首领墨菲斯。 墨菲斯告诉他，现实世界其实是由一个名叫“母体”的计算机人工智能系统控制，人们就像他们饲养的动物，没有自由和思想，而尼奥就是能够拯救人类的救世主。 可是，救赎之路从来都不会一帆风顺，到底哪里才是真实的世界？

Python绘图，圣诞树，花，爱心 | Turtle篇

CPU对每个程序员来说，是个既熟悉又陌生的东西？ 如果你只知道CPU是中央处理器的话，那可能对你并没有什么用，那么作为程序员的我们，必须要搞懂的就是CPU这家伙是如何运行的，尤其要搞懂它里面的寄存器是怎么一回事，因为这将让你从底层明白程序的运行机制。 随我一起，来好好认识下CPU这货吧 把CPU掰开来看 对于CPU来说，我们首先就要搞明白它是怎么回事，也就是它的内部构造，当然，CPU那么牛的一个东

2020年1月17日，国家统计局发布了2019年国民经济报告，报告中指出我国人口突破14亿。 猪哥的朋友圈被14亿人口刷屏，但是很多人并没有看到我国复杂的人口问题：老龄化、男女比例失衡、生育率下降、人口红利下降等。 今天我们就来分析一下我们国家的人口数据吧！ 一、背景 1.人口突破14亿 2020年1月17日，国家统计局发布了 2019年国民经济报告 ，报告中指出：年末中国大陆总人口（包括31个

2020年的1月，我辞掉了我的第一份工作

Java坑人面试题系列: 包装类（中级难度）
Java Magazine上面有一个专门坑人的面试题系列: https://blogs.oracle.com/javamagazine/quiz-2。 这些问题的设计宗旨，主要是测试面试者对Java语言的了解程度，而不是为了用弯弯绕绕的手段把面试者搞蒙。 如果你看过往期的问题，就会发现每一个都不简单。 这些试题模拟了认证考试中的一些难题。 而 “中级(intermediate)” 和 “高级(ad

By 超神经场景描述：昨天 2 月 3 日，是大部分城市号召远程工作的第一天，全国有接近 2 亿人在家开始远程办公，钉钉上也有超过 1000 万家企业活跃起来。关键词：十一出行 人脸...
Java基础知识点梳理
Java基础知识点梳理 摘要： 虽然已经在实际工作中经常与java打交道，但是一直没系统地对java这门语言进行梳理和总结，掌握的知识也比较零散。恰好利用这段时间重新认识下java，并对一些常见的语法和知识点做个总结与回顾，一方面为了加深印象，方便后面查阅，一方面为了学好java打下基础。 Java简介 java语言于1995年正式推出，最开始被命名为Oak语言，由James Gosling（詹姆
2020年全新Java学习路线图，含配套视频，学完即为中级Java程序员！！

B 站上有哪些很好的学习资源?

Web播放器解决了在手机浏览器和PC浏览器上播放音视频数据的问题，让视音频内容可以不依赖用户安装App，就能进行播放以及在社交平台进行传播。在视频业务大数据平台中，播放数据的统计分析非常重要，所以Web播放器在使用过程中，需要对其内部的数据进行收集并上报至服务端，此时，就需要对发生在其内部的一些播放行为进行事件监听。 那么Web播放器事件监听是怎么实现的呢？ 01 监听事件明细表 名...