python十进制转换二进制代码

Question

小数部分函数单独运行结果正确，但是一加整数部分函数，小数部分函数运行结果就不正确了。

number = eval(input('请输入一个十进制数：'))
#转二进制：
#整数部分：
b_number = number
xb_number = b_number - int(b_number)
xb_new_list = b_new_list = []
xB_number = B_number = ''
while b_number != 0:
    by_number = b_number % 2
    b_new_list.append(by_number)
    b_number //= 2
b_new_list.reverse()  
for Bin in b_new_list:
    B_number =B_number + str(Bin)[0:1]    
#小数部分：
while xb_number != 0:
    xb_number = xb_number * 2
    xb_new_list.append(int(xb_number))
    xb_number = xb_number - int(xb_number)
for x_Bin in xb_new_list :
    xB_number += str(x_Bin)[0:1]
print('对应的二进制数为：',B_number + '.' + xB_number)

Answer 1

while b_number != 0:
这里b_number是浮点数啊，应该用其整数部分吧

Answer 2

你这初始值不是个空嘛