字典的问题 Dictionary

Description

Authors of the new, all-in-one encyclopedia have organized the titles in the order they consider most appropriate for their readers. It's not always alphabetical, because they want to observe some peculiar relationships between them. However, they still want to allow users to look up titles quickly.

They achieve this by adding a carefully calculated number of spaces before every title in the list of titles. They call this structure a dictionary.

A dictionary is represented by a list of words with some number of spaces before certain words. Dictionary format can be described as a set of constraints on sequences of consecutive words starting with the same letter. Any maximal sequence of consecutive words starting with the same letter should satisfy the following rules:

The first word in the group has no spaces before it. Every subsequent word in the group has at least one leading space.
If
the first word of the group is deleted and
one space is deleted before every remaining word and
the first letter is deleted from every remaining word

then resulting sequence is a dictionary.

The authors don't feel like giving you a more detailed explanation of what a dictionary is, so they have included an example (see sample input and output) that clarifies their definition.
Your task is to write a program that will convert a given list of words into a dictionary by adding some number of spaces before certain words and preserving the original order of the words.
Input

The input consists of at least one and most 100000 words. Each word consists of at least one and at most 10 lower-case letters. There will be no leading or trailing spaces. There will be no blank lines between the words, but there may be an arbitrary number of blank lines at the end of the file.
Output

Write to the output the original words in the same order without any trailing spaces but with the appropriate number of leading spaces, so that this word list is a dictionary. There should be no blank lines between the words, but there may be an arbitrary number of blank lines at the end of the file.
Sample Input

a
ant
antique
amaze
bargain
bridge
bride
bribe
born
bucket
tart
tan
tram
trolley
t
try
trial
zed
double
dorm
do
dormant
donate
again
agony
boost
back
born
Sample Output

a
ant
antique
amaze
bargain
bridge
bride
bribe
born
bucket
tart
tan
tram
trolley
t
try
trial
zed
double
dorm
do
dormant
donate
again
agony
boost
back
born

Csdn user default icon
上传中...
上传图片
插入图片
抄袭、复制答案,以达到刷声望分或其他目的的行为,在CSDN问答是严格禁止的,一经发现立刻封号。是时候展现真正的技术了!
其他相关推荐
关于字典程序的实现,Dictionary
Description Authors of the new, all-in-one encyclopedia have organized the titles in the order they consider most appropriate for their readers. It's not always alphabetical, because they want to observe some peculiar relationships between them. However, they still want to allow users to look up titles quickly. They achieve this by adding a carefully calculated number of spaces before every title in the list of titles. They call this structure a dictionary. A dictionary is represented by a list of words with some number of spaces before certain words. Dictionary format can be described as a set of constraints on sequences of consecutive words starting with the same letter. Any maximal sequence of consecutive words starting with the same letter should satisfy the following rules: The first word in the group has no spaces before it. Every subsequent word in the group has at least one leading space. If the first word of the group is deleted and one space is deleted before every remaining word and the first letter is deleted from every remaining word then resulting sequence is a dictionary. The authors don't feel like giving you a more detailed explanation of what a dictionary is, so they have included an example (see sample input and output) that clarifies their definition. Your task is to write a program that will convert a given list of words into a dictionary by adding some number of spaces before certain words and preserving the original order of the words. Input The input consists of at least one and most 100000 words. Each word consists of at least one and at most 10 lower-case letters. There will be no leading or trailing spaces. There will be no blank lines between the words, but there may be an arbitrary number of blank lines at the end of the file. Output Write to the output the original words in the same order without any trailing spaces but with the appropriate number of leading spaces, so that this word list is a dictionary. There should be no blank lines between the words, but there may be an arbitrary number of blank lines at the end of the file. Sample Input a ant antique amaze bargain bridge bride bribe born bucket tart tan tram trolley t try trial zed double dorm do dormant donate again agony boost back born Sample Output a ant antique amaze bargain bridge bride bribe born bucket tart tan tram trolley t try trial zed double dorm do dormant donate again agony boost back born
C# Dictionary这种 字典嵌套如何循环遍历呢
![图片说明](https://img-ask.csdn.net/upload/201703/29/1490752933_315464.png) 这种嵌套的dictionary该如何遍历呢
KSVD程序中要求信号Y的列数要大于字典D的列数,不知道为什么有这个要求。
用KSVD.m训练字典,程序中有一段要求信号Y的列数要大于字典D的列数,否则就会报错,但是理论上并不需要这个要求,帮忙解释下为什么会有这个要求?(程序第91行)如果Y是n*1的向量,就不能训练出字典了吗? ``` function [Dictionary,output] = KSVD(... Data,... % an nXN matrix that contins N signals (Y), each of dimension n. param) % ========================================================================= % K-SVD algorithm % ========================================================================= % The K-SVD algorithm finds a dictionary for linear representation of % signals. Given a set of signals, it searches for the best dictionary that % can sparsely represent each signal. Detailed discussion on the algorithm % and possible applications can be found in "The K-SVD: An Algorithm for % Designing of Overcomplete Dictionaries for Sparse Representation", written % by M. Aharon, M. Elad, and A.M. Bruckstein and appeared in the IEEE Trans. % On Signal Processing, Vol. 54, no. 11, pp. 4311-4322, November 2006. % ========================================================================= % INPUT ARGUMENTS: % Data an nXN matrix that contins N signals (Y), each of dimension n. % param structure that includes all required % parameters for the K-SVD execution. % Required fields are: % K, ... the number of dictionary elements to train % K 原子个数 % numIteration,... number of iterations to perform. % numIteration 迭代次数 % errorFlag... if =0, a fix number of coefficients is % used for representation of each signal. If so, param.L must be % specified as the number of representing atom. if =1, arbitrary number % of atoms represent each signal, until a specific representation error % is reached. If so, param.errorGoal must be specified as the allowed % error. % preserveDCAtom... if =1 then the first atom in the dictionary % is set to be constant, and does not ever change. This % might be useful for working with natural % images (in this case, only param.K-1 % atoms are trained). % (optional, see errorFlag) L,... % maximum coefficients to use in OMP coefficient calculations. % (optional, see errorFlag) errorGoal, ... % allowed representation error in representing each signal. % InitializationMethod,... mehtod to initialize the dictionary, can % be one of the following arguments: % * 'DataElements' (initialization by the signals themselves), or: % * 'GivenMatrix' (initialization by a given matrix param.initialDictionary). % (optional, see InitializationMethod) initialDictionary,... % if the initialization method % is 'GivenMatrix', this is the matrix that will be used. % (optional) TrueDictionary, ... % if specified, in each % iteration the difference between this dictionary and the trained one % is measured and displayed. % displayProgress, ... if =1 progress information is displyed. If param.errorFlag==0, % the average repersentation error (RMSE) is displayed, while if % param.errorFlag==1, the average number of required coefficients for % representation of each signal is displayed. % ========================================================================= % OUTPUT ARGUMENTS: % Dictionary The extracted dictionary of size nX(param.K). % output Struct that contains information about the current run. It may include the following fields: % CoefMatrix The final coefficients matrix (it should hold that Data equals approximately Dictionary*output.CoefMatrix. % ratio If the true dictionary was defined (in % synthetic experiments), this parameter holds a vector of length % param.numIteration that includes the detection ratios in each % iteration). % totalerr The total representation error after each % iteration (defined only if % param.displayProgress=1 and % param.errorFlag = 0) % numCoef A vector of length param.numIteration that % include the average number of coefficients required for representation % of each signal (in each iteration) (defined only if % param.displayProgress=1 and % param.errorFlag = 1) % ========================================================================= if (~isfield(param,'displayProgress')) param.displayProgress = 0; end totalerr(1) = 99999; if (isfield(param,'errorFlag')==0) param.errorFlag = 0; end if (isfield(param,'TrueDictionary')) displayErrorWithTrueDictionary = 1; ErrorBetweenDictionaries = zeros(param.numIteration+1,1); ratio = zeros(param.numIteration+1,1); else displayErrorWithTrueDictionary = 0; ratio = 0; end if (param.preserveDCAtom>0) FixedDictionaryElement(1:size(Data,1),1) = 1/sqrt(size(Data,1)); else FixedDictionaryElement = []; end % coefficient calculation method is OMP with fixed number of coefficients if (size(Data,2) < param.K)% 问题在这里,Data的列小于K就不能运行 disp('Size of data is smaller than the dictionary size. Trivial solution...'); Dictionary = Data(:,1:size(Data,2)); return; elseif (strcmp(param.InitializationMethod,'DataElements')) Dictionary(:,1:param.K-param.preserveDCAtom) = Data(:,1:param.K-param.preserveDCAtom); elseif (strcmp(param.InitializationMethod,'GivenMatrix')) Dictionary(:,1:param.K-param.preserveDCAtom) = param.initialDictionary(:,1:param.K-param.preserveDCAtom); end % reduce the components in Dictionary that are spanned by the fixed % elements if (param.preserveDCAtom) tmpMat = FixedDictionaryElement \ Dictionary; Dictionary = Dictionary - FixedDictionaryElement*tmpMat; end %normalize the dictionary. 对字典进行归一化 Dictionary = Dictionary*diag(1./sqrt(sum(Dictionary.*Dictionary))); Dictionary = Dictionary.*repmat(sign(Dictionary(1,:)),size(Dictionary,1),1); totalErr = zeros(1,param.numIteration); %% % the K-SVD algorithm starts here. for iterNum = 1:param.numIteration %param.numIteration = numIterOfKsvd=10 % find the coefficients if (param.errorFlag==0) %param.errorFlag = 1; %CoefMatrix = mexOMPIterative2(Data, [FixedDictionaryElement,Dictionary],param.L); CoefMatrix = OMP([FixedDictionaryElement,Dictionary],Data, param.L); %size(Data,2)=249*249 else %CoefMatrix = mexOMPerrIterative(Data, [FixedDictionaryElement,Dictionary],param.errorGoal); CoefMatrix = OMPerr([FixedDictionaryElement,Dictionary],Data, param.errorGoal);%%%%%%%%%%param.errorGoal = sigma*C; 稀疏矩阵 param.L = 1; end replacedVectorCounter = 0; rPerm = randperm(size(Dictionary,2)); for j = rPerm [betterDictionaryElement,CoefMatrix,addedNewVector] = I_findBetterDictionaryElement(Data,... [FixedDictionaryElement,Dictionary],j+size(FixedDictionaryElement,2),... CoefMatrix,param.L); Dictionary(:,j) = betterDictionaryElement; if (param.preserveDCAtom) tmpCoef = FixedDictionaryElement\betterDictionaryElement; Dictionary(:,j) = betterDictionaryElement - FixedDictionaryElement*tmpCoef; Dictionary(:,j) = Dictionary(:,j)./sqrt(Dictionary(:,j)'*Dictionary(:,j)); end replacedVectorCounter = replacedVectorCounter+addedNewVector; end if (iterNum>1 & param.displayProgress) if (param.errorFlag==0) output.totalerr(iterNum-1) = sqrt(sum(sum((Data-[FixedDictionaryElement,Dictionary]*CoefMatrix).^2))/prod(size(Data))); disp(['Iteration ',num2str(iterNum),' Total error is: ',num2str(output.totalerr(iterNum-1))]); else %执行此句 output.numCoef(iterNum-1) = length(find(CoefMatrix))/size(Data,2); disp(['Iteration ',num2str(iterNum),' Average number of coefficients: ',num2str(output.numCoef(iterNum-1))]); end end if (displayErrorWithTrueDictionary ) [ratio(iterNum+1),ErrorBetweenDictionaries(iterNum+1)] = I_findDistanseBetweenDictionaries(param.TrueDictionary,Dictionary);%%%%%% disp(strcat(['Iteration ', num2str(iterNum),' ratio of restored elements: ',num2str(ratio(iterNum+1))])); output.ratio = ratio; end Dictionary = I_clearDictionary(Dictionary,CoefMatrix(size(FixedDictionaryElement,2)+1:end,:),Data); if (isfield(param,'waitBarHandle')) waitbar(iterNum/param.counterForWaitBar); end end output.CoefMatrix = CoefMatrix; Dictionary = [FixedDictionaryElement,Dictionary]; function [betterDictionaryElement,CoefMatrix,NewVectorAdded] = I_findBetterDictionaryElement(Data,Dictionary,j,CoefMatrix,numCoefUsed) if (length(who('numCoefUsed'))==0) numCoefUsed = 1; % liu=1%%%%没有进行此句,说明if条件不满足。 end relevantDataIndices = find(CoefMatrix(j,:)); % the data indices that uses the j'th dictionary element. 查找出系数矩阵中每一行中非0元素的序号 参考DCT字典的程序:relevantDataIndices = find(Coefs(3,:)); if (length(relevantDataIndices)<1) %(length(relevantDataIndices)==0) 如果系数矩阵为空,则进行如下的语句 。 如果relevantDataIndices为0,说明没有patch表达粗腰用到第j个原子 ErrorMat = Data-Dictionary*CoefMatrix; ErrorNormVec = sum(ErrorMat.^2); [d,i] = max(ErrorNormVec); betterDictionaryElement = Data(:,i);%ErrorMat(:,i); % betterDictionaryElement = betterDictionaryElement./sqrt(betterDictionaryElement'*betterDictionaryElement);%归一化 betterDictionaryElement = betterDictionaryElement.*sign(betterDictionaryElement(1)); CoefMatrix(j,:) = 0; NewVectorAdded = 1%%%%%实验证明(针对w.jpg图像),值累加了一次 % liuzhe=1 没进行此句,说明稀疏矩阵的每一行都有非零的元素 return; end NewVectorAdded = 0; tmpCoefMatrix = CoefMatrix(:,relevantDataIndices); %将稀疏矩阵中非0 的取出来 tmpCoefMatrix尺寸为:256*length(relevantDataIndices) tmpCoefMatrix(j,:) = 0;% the coeffitients of the element we now improve are not relevant. errors =(Data(:,relevantDataIndices) - Dictionary*tmpCoefMatrix); % vector of errors that we want to minimize with the new element D:64*256 tmpCoefMatrix尺寸为:256*length(relevantDataIndices) Data(:,relevantDataIndices):64*relevantDataIndices % % the better dictionary element and the values of beta are found using svd. % % This is because we would like to minimize || errors - beta*element ||_F^2. % % that is, to approximate the matrix 'errors' with a one-rank matrix. This % % is done using the largest singular value. %%在这里使用SVD就可以达到|| errors - beta*element ||_F^2误差最小的效果 [betterDictionaryElement,singularValue,betaVector] = svds(errors,1);%%%%%%%仅仅取出了第一主分量 errors的大小为;64*relevantDataIndices M=64 N=relevantDataIndices betterDictionaryElement*singularValue*betaVector'近似的可以表示errors %a=[1 2 3 4;5 6 7 8;9 10 11 12;2 4 6 7.99999]; [u,s,v]=svds(a) u*s*v' [u,s,v]=svds(a,1):取出的第一主成分 %对于svds函数:a为M*N的矩阵,那么u:M*M S:M*N(简写成M*M) V=N*M V'=M*N %对于svd函数:a为M*N的矩阵, 那么u:M*M S:M*N V=N*N V'=N*N %将字典原子D的解定义为U中的第一列,将系数向量CoefMatrix的解定义为V的第一列与S(1,1)的乘积 这个是核心 核心 核心!!!!!!!!!!!!!!! CoefMatrix(j,relevantDataIndices) = singularValue*betaVector';% *signOfFirstElem s*v' [u,s,v]=svds(a,1):取出的第一主成分 ,所以此时s*v'矩阵大小为 1*N,即CoefMatrix(j,relevantDataIndices)也为:1*N betterDictionaryElement:M*1,即64*1的向量 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % findDistanseBetweenDictionaries %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% function [ratio,totalDistances] = I_findDistanseBetweenDictionaries(original,new) % first, all the column in oiginal starts with positive values. catchCounter = 0; totalDistances = 0; for i = 1:size(new,2) new(:,i) = sign(new(1,i))*new(:,i); end for i = 1:size(original,2) d = sign(original(1,i))*original(:,i); distances =sum ( (new-repmat(d,1,size(new,2))).^2); [minValue,index] = min(distances); errorOfElement = 1-abs(new(:,index)'*d); totalDistances = totalDistances+errorOfElement; catchCounter = catchCounter+(errorOfElement<0.01); end ratio = 100*catchCounter/size(original,2); %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % I_clearDictionary %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% function Dictionary = I_clearDictionary(Dictionary,CoefMatrix,Data) T2 = 0.99; T1 = 3; K=size(Dictionary,2); %%K=256 Er=sum((Data-Dictionary*CoefMatrix).^2,1); % remove identical atoms(删除相同的原子) 列求和 CoefMatrix(j,relevantDataIndices)的大小为256*relevantDataIndices G=Dictionary'*Dictionary; %256*256 G表示不同的原子求内积,可以认为是计算相似性 G 的大小是 K*K G = G-diag(diag(G));%例如:G=magic(3) diag(diag(G)) 也就是将对角的元素赋值为0 for jj=1:1:K, if max(G(jj,:))>T2 | length(find(abs(CoefMatrix(jj,:))>1e-7))<=T1 , %G(jj,:))>T2 表示两个原子间相似性很高,大于0.99 %length(find(abs(CoefMatrix(jj,:))>1e-7) 表示这使用到第jj个原子的patch少于3个 [val,pos]=max(Er); clearDictionary=1%%%%%%%%%%%%%%%%%%%%%%%%测试满足if条件的有多少次 Er(pos(1))=0;%将最大误差处的值赋值为0 Dictionary(:,jj)=Data(:,pos(1))/norm(Data(:,pos(1)));%%norm(Data(:,pos(1)):求向量的模 此整句相当于把误差最大的列归一化 G=Dictionary'*Dictionary; G = G-diag(diag(G)); end; end; ```
C# 微信红包接口开发 Dictionary如何变成xml
小弟初学,根据网上的一些资料,用C#开发微信红包调用接口,现在遇到的问题是, 构造出来的字典, 现在不知道怎么将Dictionary转换为微信接口需要的xml格式,请大神们赐教! Dictionary<string,string> parameters = new Dictionary<string,string>(); parameters.Add("act_name", act_name); parameters.Add("client_ip", client_ip); parameters.Add("min_value", min_value); parameters.Add("max_value", max_value); parameters.Add("mch_billno", mch_billno); parameters.Add("mch_id", mch_id); parameters.Add("nonce_str", nonce_str); parameters.Add("nick_name", nick_name); parameters.Add("re_openid", re_openid); parameters.Add("remark", remark); parameters.Add("send_name", send_name); parameters.Add("total_num", total_num); parameters.Add("total_amount", total_amount); parameters.Add("wishing", wishing); parameters.Add("wxappid", wxappid); //生成签名 string sign = Class1.CreateSignString(parameters, "Qwertyuiopasdfghjklzxcvbnm098765"); parameters.Add("sign", sign);
(自己搞定了)C++编写一个在单词本内单词测试的程序,求大佬捉虫
1.错误代码LINK2019,LINK1120 ``` #include "exam.h" #include "ui.h" #include <iostream> #include <string> #include "stdlib.h" #include "time.h" using namespace std; static const string exam_ui_prompt = "\n\n" "\t|*******************************|\n" "\t|* 请您选择考试类别 *|\n" "\t|* 1 看中文写英文 *|\n" "\t|* 2 看英文写中文 *|\n" "\t|* 3 看解释写成语 *|\n" "\t|* 0 返回上级 *|\n" "\t 请输入(1,2,3或0): "; void exam_ui() { void exam_ui_english_for_chinese(); { //装载词库 dict_load( &dictionaries[ENGLISH_CHINESE], DICT_PATH DICT_ENGLISH_CHINESE ); //生成考试题目 Examination exam; exam_create(&exam, &dictionaries[ENGLISH_CHINESE]); for (int i = 0; i < exam.words.size(); i++) { CLEAR(); cout << "\n\n"; cout << "\t|**************************|\n"; meaning_display(exam.meanings[i]); cout << "\n"; cout << "\t|*************************|\n"; string word = get_input_string("\t 请输入英文答案(0 退出) : "); cout << "\t 请输入英文答案 (0 退出):"; std::getline(cin, word); if (word == exam.words[i]) { cout << "\t 正确!!!" << endl; string op = get_input_string("\t 请输入(0 退出, 其他 下一题):"); if (bool op = "0") { break; } } else if (word == "0") { break; } else { cout << "\t 错误, 继续加油哦" << endl; //继续下去还答这道题 i--; } } } CLEAR(); cout << exam_ui_prompt; string op; std::getline(cin, op); if (op == "1") { exam_ui_english_for_chinese(); } else if (op == "2") { } else if (op == "0") { return; } exam_ui(); } /** 生成一个[min,max)之间的随机整数 */ static int radom_index(int min, int max) { return (int)(min + (double)rand() / (double)RAND_MAX * (max - min)); } /* 从字典随机生成一个试卷 */ void exam_create(Examination* exam, Dictionary* dict) { srand(time(NULL)); int wordcount = dict->words.size(); int itemcount = wordcount < 10 ? wordcount : 10; for (int i = 0; i < itemcount; i++) { int idx = radom_index(0, wordcount); exam->words.push_back(dict->words[idx]); exam->meanings.push_back(dict->meanings[idx]); } } void exam_ui_display() { return; } void exam_ui_chinese_for_english() { return; } void exam_ui_english_for_chinese() { } ``` 3.我看我的头文件里都声明定义了但我还是不知道怎么解决这个错误 ``` #ifndef _EXAM_H #define _EXAM_H #include <string> #include <vector> #include "dict.h" using namespace std; typedef struct { vector<string>words; vector< vector < string > >meanings; }Examination; void exam_create(Examination* exam, Dictionary* dict); void exam_ui_display(); void exam_ui_chinese_for_english(); void exam_ui_english_for_chinese(); bool op; string word; #endif//!_EXAM_H ```
将给定的单词列表转换为字典的算法原理,是如何使用C语言的程序编写设计的思想方法的代码怎么来做
Description Authors of the new, all-in-one encyclopedia have organized the titles in the order they consider most appropriate for their readers. It's not always alphabetical, because they want to observe some peculiar relationships between them. However, they still want to allow users to look up titles quickly. They achieve this by adding a carefully calculated number of spaces before every title in the list of titles. They call this structure a dictionary. A dictionary is represented by a list of words with some number of spaces before certain words. Dictionary format can be described as a set of constraints on sequences of consecutive words starting with the same letter. Any maximal sequence of consecutive words starting with the same letter should satisfy the following rules: The first word in the group has no spaces before it. Every subsequent word in the group has at least one leading space. If the first word of the group is deleted and one space is deleted before every remaining word and the first letter is deleted from every remaining word then resulting sequence is a dictionary. The authors don't feel like giving you a more detailed explanation of what a dictionary is, so they have included an example (see sample input and output) that clarifies their definition. Your task is to write a program that will convert a given list of words into a dictionary by adding some number of spaces before certain words and preserving the original order of the words. Input The input consists of at least one and most 100000 words. Each word consists of at least one and at most 10 lower-case letters. There will be no leading or trailing spaces. There will be no blank lines between the words, but there may be an arbitrary number of blank lines at the end of the file. Output Write to the output the original words in the same order without any trailing spaces but with the appropriate number of leading spaces, so that this word list is a dictionary. There should be no blank lines between the words, but there may be an arbitrary number of blank lines at the end of the file. Sample Input a ant antique amaze bargain bridge bride bribe born bucket tart tan tram trolley t try trial zed double dorm do dormant donate again agony boost back born Sample Output a ant antique amaze bargain bridge bride bribe born bucket tart tan tram trolley t try trial zed double dorm do dormant donate again agony boost back born
hanlp自定义字典不起作用
配置的地址没有报错, root=D:// CustomDictionaryPath=data/dictionary/custom/CustomDictionary.txt;CompanyName.txt;school.txt; 字典(school.txt): 上海财经大学 ntu 1 上海交通大学 ntu 1 复旦大学 ntu 1 北京大学 ntu 1 清华大学 ntu 1 中国科学技术大学 ntu 1 浙江大学 ntu 1 中国人民大学 ntu 1 对外经济贸易大学 ntu 1 中央财经大学 ntu 1 同济大学 ntu 1 外交学院 ntu 1 上海外国语大学 ntu 1 北京外国语大学 ntu 1 北京航空航天大学 ntu 1 .... 方法这样调用: Segment segment = HanLP.newSegment().enableCustomDictionary(true); final List<Term> schoolList = segment.seg(content); 但我定义的词和词性还是没有按照我设置的词进行分词, 例如我在自己的分词txt文件中设置了 浙江大学 ntu 1, 但分词后还是分成了 浙江 nt,大学 n,请大神指点一二
Python, list of dictionaries遍历筛选
![图片说明](https://img-ask.csdn.net/upload/201908/27/1566910503_255777.png) 说明:原始数据导进来,index3是字符串格式(json)。 需求:提取index3里字典格式下所有“name”的值。 现有思路:用json.loads转码成list of dictionaries格式,然后循环遍历index3,遍历list所有字典,遍历字典里的key值,判断字典key=="name",取value。 说明:同一个list里面多个dictionary,且key值有重复;json转码前带单引号字符串str。 **问题:三层循环,数据量稍微大一点速度极慢,求大神帮帮忙有没有新的思路!**
关于python函数递归返回值的问题
这是一个匹配字典中词语的函数。 按理说已经匹配成功了 在return之前加个print 输出结果是对的 但是在外面调用输出来就是None 不知道为什么 求大神!! ``` def find_word(dictionary,word): if word in dictionary: return word else: if len(word)-1 == 0: return word else: word = word[0:len(word)-1] find_word(dictionary,word) dictionary = read_dic() print(find_word(dictionary,"热烈欢迎新")) ```
在数据字典表存储的类型在导出excel的时候应该怎么转变?
var filetype = ModelHelper.EntityModel.Query<T_AH_DICTIONARY>().FirstOrDefault(e => e.DICTIONARYID == alist.FILETYPE); rowtemp.CreateCell(3).SetCellValue(filetype.ToString() ?? "".ToString()); 这是我的转变格式导出的时候是导出了表名== 想请问一下应该怎么写?
.Net FW4.0的HttpClient疑似bug问题怎么解决?
使用HttpClient.SendAsync时,request实参中的Uri斜杠('/')被Url解码导致请求Url错误,返回404,如何防止这种解码? 4.5已经试过没有这个问题. 以下是代码片段: ``` apiClient = new HttpClient {BaseAddress = new Uri("http://...")}; ``` ``` var request = new HttpRequestMessage(HttpMethod.Post, "accessToken/getAccessToken"); request.AddMatrixParam(new Dictionary<string, string> { ["encryptStr"] = encryptStr, ["timestamp"] = timestamp.ToString() }); ``` AddMatrixParam方法是将字典转化为Matrix格式的url参数,然后拼接到url上,这个方法的操作结果确认没有问题 ``` Debug.WriteLine($"Request URL: {request.RequestUri}"); var response = apiClient.SendAsync(request).Result; Debug.WriteLine($"Request URL: {request.RequestUri}"); ``` 输出: > Request URL: accessToken/getAccessToken;encryptStr%3dPoB3dUXFGAaN3ZEcovdYgBp6GSu6ECvqIaSPvLgEWp5Ml%2fAkD5sbqWlqUTcqUoV0CTU3%2b%2bUvVYA%2f94bjj%2fAHv%2bXnFRIT8xjFCiKgLG94sx8%3d%3btimestamp%3d1565949032 > Request URL: http://.../accessToken/getAccessToken;encryptStr=PoB3dUXFGAaN3ZEcovdYgBp6GSu6ECvqIaSPvLgEWp5Ml/AkD5sbqWlqUTcqUoV0CTU3++UvVYA/94bjj/AHv+XnFRIT8xjFCiKgLG94sx8=;timestamp=1565949032 请求发送前后的相对url部分是不一样的,"/"被莫名其妙得解码了出来
asp.net core+EF架构查询数据库时报错
asp.net core+EF架构查询数据库时报错 Entities代码 ``` [Table("Dictionary")] [Serializable] public partial class Dictionary { /// <summary> /// 数据字典ID /// </summary> public Guid Id { get; set; } /// <summary> /// 字典名称 /// </summary> public string Name { get; set; } /// <summary> /// 字典编码 /// </summary> public string Code { get; set; } /// <summary> /// 数据类型 /// </summary> public int? Type { get; set; } /// <summary> /// 父级ID /// </summary> public Guid Pid { get; set; } /// <summary> /// 排序权重 /// </summary> public int? Sort { get; set; } /// <summary> /// 是否启用 /// </summary> public bool Enabled { get; set; } /// <summary> /// 是否删除 /// </summary> public bool Deleted { get; set; } /// <summary> /// 创建用户ID /// </summary> public Guid CreateId { get; set; } /// <summary> /// 创建日期 /// </summary> public DateTime? CreateTime { get; set; } /// <summary> /// 更新用户ID /// </summary> public Guid UpdateId { get; set; } /// <summary> ///更新日期 /// </summary> public DateTime? UpdateTime { get; set; } /// <summary> /// 备注 /// </summary> public string Remark { get; set; } } 上下文代码 public class EntityDbContext : DbContext { public EntityDbContext(DbContextOptions options) : base(options) { } public DbSet<Category> Categories { get; set; } public DbSet<SysUser> SysUsers { get; set; } public DbSet<SysUserToken> SysUserTokenes { get; set; } public DbSet<SysUserLoginLog> SysUserLoginLogs { get; set; } public DbSet<SysUserRole> SysUserRoles { get; set; } public DbSet<SysPermission> SysPermissions { get; set; } public DbSet<Dictionary> Dictionaries { get; set; } } 调用代码 private IRepository<Entities.Dictionary> _dictionaryRepository; private IHttpContextAccessor _accessor; public DictionaryService(IRepository<Entities.Dictionary> dictionaryRepository, IHttpContextAccessor accessor) { this._dictionaryRepository = dictionaryRepository; this._accessor = accessor; } /// <summary> /// 获取所有数据字典并缓存 /// </summary> /// <returns></returns> public List<Entities.Dictionary> getAll() { var result = _dictionaryRepository.Table.Where(o => !o.Deleted); var ex = result.Expression; //result = result.Where(o => o.Code == "KGJ-2019-T-001" || o.Code == "KGJ-2019-T-002"); //return result.OrderBy(o => o.Type).ThenBy(o => o.CreateTime).ToList(); throw new NotImplementedException(ex.ToString()); } ``` 报错问题:![图片说明](https://img-ask.csdn.net/upload/201908/27/1566883198_22483.png)
C#若不使用指针,如何存储和读取从一个基类派生的多种派生类?
各位专家好!设有一个基类BaseMan,派生了多种派生类BatMan、SuperMan、SpiderMan……示例如下: ``` class BaseMan { int m_ID; public virtual void DoSomething() { } //此处省略大量无关的代码 } class BatMan:BaseMan { public override void DoSomething() { //动作1 } //此处省略大量无关的代码 } class SuperMan:BaseMan { public override void DoSomething() { //动作2 } //此处省略大量无关的代码 } …… ``` 现在期望实现以下2个功能,其中功能2实现不了,求指点,感谢! 功能1、用1个数组统一存储所有派生类的对象(每个对象有唯一标识的ID)——已实现,代码如下: ``` class ManManager { Dictionary<int, BaseMan> dicMan = new Dictionary<int, BaseMan>(); public void RegisterMan(int id,BaseMan man) { dicMan.Add(id,man); } //此处省略大量无关的代码 } ``` 功能2、通过ID读取对象,并调用对象中的DoSomething——未实现。我的代码如下,调试发现实际调用的是基类的DoSomething,请问这个程序应该怎么修改呢? ``` //第1步,在ManManager中增加一个接口GetManFromID class ManManager { Dictionary<int, BaseMan> dicMan = new Dictionary<int, BaseMan>(); public void RegisterMan(int id,BaseMan man) { dicMan.Add(id,man); } public BaseMan GetManFromID(int id) { return dicMan[id]; } //此处省略大量无关的代码 } //第2步,在主函数中建立对象,并把各种Man存到字典里 ManManager mm=new ManManager(); BatMan man1=new BatMan(); SuperMan man2=new SuperMan(); mm.RegisterMan(1,man1); mm.RegisterMan(2,man2); //第3步,通过ID读出对象,结果出了问题 mm.GetManFromID(1).DoSomething();//这句执行的DoSomething,实际为基类BaseMan的DoSomething,而我期望执行的是ID=1的对象的DoSomething ```
抓包的时候字典里面没有值。
为什么这个会有错误呢? 谁有类似的demo吗? private void btnLogin_Click(object sender, EventArgs e) { string username = txtUserName.Text; string password = txtPwd.Text; HttpItem itemSign = new HttpItem() { URL = "https://account.xiaomi.com/pass/serviceLogin", }; HttpHelper helperSign = new HttpHelper(); HttpResult resultSign = helperSign.GetHtml(itemSign); string signHtml = resultSign.Html; txtInfo.Text = signHtml; HtmlAgilityPack.HtmlDocument doc = new HtmlAgilityPack.HtmlDocument(); doc.LoadHtml(signHtml); var htmlnodes = doc.DocumentNode.Descendants(); Dictionary<string, string> dict = new Dictionary<string, string>(); foreach (var item in htmlnodes) { if (item.Attributes["name"] != null && item.Attributes["value"] != null) { dict.Add(item.Attributes["name"].Value, item.Attributes["value"].Value); } } string passToken = HttpUtility.UrlEncode(dict["passToken"]); string callback = HttpUtility.UrlEncode(dict["callback"]); string sid = HttpUtility.UrlEncode(dict["sid"]); string qs = HttpUtility.UrlEncode(dict["qs"]); string hidden = HttpUtility.UrlEncode(dict["hidden"]); string _sign = HttpUtility.UrlEncode(dict["_sign"]); string auto = HttpUtility.UrlEncode(dict["auto"]); cookies = resultSign.Cookie; HttpItem itemLogin = new HttpItem() //登陆Post { URL = "https://account.xiaomi.com/pass/serviceLoginAuth2", Method = "POST", Cookie = cookies, Referer = "https://account.xiaomi.com/pass/serviceLogin", ContentType = "application/x-www-form-urlencoded", Postdata = string.Format("passToken={0}&user={1}&pwd={2}&callback={3}&sid={4}&qs={5}&hidden={6}&_sign={7}&auto={8}", passToken, username, password, callback, sid, qs, hidden, _sign, auto) }; HttpHelper helperLogin = new HttpHelper(); HttpResult resultLogin = helperLogin.GetHtml(itemLogin); if (resultLogin.Html.Contains("小米帐户 - 登录")) { AppendText(username + "登陆失败\n"); return; } AppendText(username + "登陆成功"); cookies += ";" + resultLogin.Cookie; // AppendText(cookies); }
C# 的服务器向之前登陆的时候保存的客户端Socket发送数据的时候报错了
报错:The operation is not allowed on non-connected sockets. 问题是这样的,制作添加好友模块时,遇到了一个问题,就是在登录的时候,服务端会通过ID绑定那个Socket: ``` //目前在线的客户端字典,与ID绑定 Dictionary<int, Socket> DicOnlineClients; ``` 绑定: ``` //向目前在线的客户端列表添加这个客户端 DicOnlineClients.Add(playerID, packet._peer); ``` 然后发送好友请求的时候会通过这个ID发到与这个ID绑定的Socket上,前提是这个客户端没有离线 ``` //获取此ID的Socket Socket socket; if (DicOnlineClients.TryGetValue(FriendID,out socket)) { _server.Send(SendStream, socket); } ``` 但是问题出在,在Send的时候,报错了 The operation is not allowed on non-connected sockets. 可是我客户端的socket明明是在线的啊 请大神帮忙解答下。或者有没有其他的方法,用于向指定的客户端发送数据的,我这里用的是通过玩家ID辨识
Edit.jsp取值问题,onchange问题,求大神指导
我在edit.jsp为客户设计随写随算的功能,代扣卸费=代扣卸费单价*实际重量。利用onchange 在实际重量数据改变时,代扣卸费自动算出来 但是我的代扣卸费单价 是字典表里的数值,我在这个页面怎么用它呢,求大神指导 ``` function setdaiKouXieFei(){ var daikouxiefei= document.getElementById("ruKu.shiJiZongLiang").value* document.getElementById("dkxf").value document.getElementById("ruKu.daiKouXieFei").value=daikouxiefei; } ``` ``` <TR> <TH align="right" width='20%'> 实际重量:</TH> <TD align="left" class="tdStyle" > <s:if test="ruKu.id>0"> <s:textfield name="ruKu.shiJiZongLiang" onchange="setdaiKouXieFei()" readonly="true" size="30"/>&nbsp; </s:if> <s:else> <s:textfield name="ruKu.shiJiZongLiang" onchange="setdaiKouXieFei()" readonly="true" size="30"/>&nbsp; </s:else> </TD> ``` ``` //代扣卸费 private ArrayList<Dictionary> dicDkxfdjList; private double dkxf; public ArrayList<Dictionary> getDicDkxfdjList() { return dicDkxfdjList; } public void setDicDkxfdjList() throws Exception{ dicDkxfdjList = coreService.getDictionaryList("dkxf"); } public double getDkxf() { return dkxf; } public void setDkxf() throws Exception{ dkxf = TypeChange.stringToDouble(dicDkxfdjList.get(0).getValue()); ```
Grid 下拉列表问题
我从后台返回一个数据集 用Grid显示 其中性别 职务都是数字 是字典ID 我打算在deferer的时候 将数字更新为汉字 [code="java"] //-->数据列 var Employee_cm = new Ext.grid.ColumnModel ([ ...... {header:'性别',dataIndex:'SexID',width:100,editor:Employee_SexCombox, renderer:function(value, cellmeta, record, rowIndex, columnIndex, store){ return GetDictionaryNameByID(record.data["SexID"]); } }, ]); //翻译字典的公共函数 function GetDictionaryNameByID(DictionaryID) { Ext.Ajax.request ({ url : 'JSON/System/Dictionary.aspx', params: { FunctionName : 'Sys_Dictionary_GetDictionaryName', DictionaryID : DictionaryID }, failure : function(response,option) { return ''; }, success : function(response,option) { if (Ext.util.JSON.decode(response.responseText).success) { var temp_infoObject = Ext.util.JSON.decode(response.responseText); return temp_infoObject.info; } else { return ''; } } }) } [/code] 但是 我发现grid每次翻译后都是空 后台返回值用FireBug调试是:{success:true,info:"男"} 请教一下大家为什么?如果我把GetDictionaryNameByID返回值写死 就可以翻译成功。。。。 [b]问题补充:[/b] Rooock: 我用调试了 数据取到后台 没有问题 蔡华江: record.data["SexID"]); 我这样写 可以取得数据 record.get("SexID"); 反倒不能得到数据 会后台报错 大家平时是怎么解决Grid字典项翻译的?也说一下 谢谢 [b]问题补充:[/b] Rooock: // 你是说这里temp_infoObject.info是男. 但是显示不了? return temp_infoObject.info; 是的 程序有运行到这里 但是最终 GetDictionaryNameByID(DictionaryID)函数返回值时空 如果我在GetDictionaryNameByID 一开始就声明一个变量StrRetrun = 在各个return的地方 给这个变量赋值 最后返回 StrRetrun变量 就发现 最终grid显示的是'ddd' 但是在FF中调试 发现确实在success : function(response,option) 的时候 给StrRetrun赋过'男'的。。。。 [b]问题补充:[/b] 蔡华江: 原来是这样 我在原理上就错误了 没有理解正确 谢谢。 请问 你是怎么解决这个问题的呢? 翻译Grid中的字典项 最好能贴段代码 小弟这里谢过
python怎么获取网卡的理论带宽?net_if_stats()中的speed指的是什么速率?
我想用Python抓到网络的使用率netUsage,计算公式为: netUsage = Bytes Total / Current Bandwidth, 现在可以用 psutil.net_io_counters()分别求得收发的速率,进而求得Bytes Total, 1.但是current bandwidth怎么求呢? 2.网上找到了一种方法是使用psutil.net_if_stats().items()中的speed参数来求,详见 https://bbs.csdn.net/topics/392055372?list=lz 但是这里的speed是什么速率呢?找了半天也没找到合适的答案 3.一块网卡,用psutil.net_io_counters(pernic=true)返回来一个字典类型有三个值,解释如下,但是没看明白什么是every network interface installed on the system(系统实际安装的网口?)求网络大神指点 If *pernic* is True return the same information for every network interface installed on the system as a dictionary with network interface names as the keys and the namedtuple described above as the values.
相见恨晚的超实用网站
搞学习 知乎:www.zhihu.com 简答题:http://www.jiandati.com/ 网易公开课:https://open.163.com/ted/ 网易云课堂:https://study.163.com/ 中国大学MOOC:www.icourse163.org 网易云课堂:study.163.com 哔哩哔哩弹幕网:www.bilibili.com 我要自学网:www.51zxw
花了20分钟,给女朋友们写了一个web版群聊程序
参考博客 [1]https://www.byteslounge.com/tutorials/java-ee-html5-websocket-example
爬虫福利二 之 妹子图网MM批量下载
爬虫福利一:27报网MM批量下载    点击 看了本文,相信大家对爬虫一定会产生强烈的兴趣,激励自己去学习爬虫,在这里提前祝:大家学有所成! 目标网站:妹子图网 环境:Python3.x 相关第三方模块:requests、beautifulsoup4 Re:各位在测试时只需要将代码里的变量 path 指定为你当前系统要保存的路径,使用 python xxx.py 或IDE运行即可。
字节跳动视频编解码面经
引言 本文主要是记录一下面试字节跳动的经历。 三四月份投了字节跳动的实习(图形图像岗位),然后hr打电话过来问了一下会不会opengl,c++,shador,当时只会一点c++,其他两个都不会,也就直接被拒了。 七月初内推了字节跳动的提前批,因为内推没有具体的岗位,hr又打电话问要不要考虑一下图形图像岗,我说实习投过这个岗位不合适,不会opengl和shador,然后hr就说秋招更看重基础。我当时
Java学习的正确打开方式
在博主认为,对于入门级学习java的最佳学习方法莫过于视频+博客+书籍+总结,前三者博主将淋漓尽致地挥毫于这篇博客文章中,至于总结在于个人,实际上越到后面你会发现学习的最好方式就是阅读参考官方文档其次就是国内的书籍,博客次之,这又是一个层次了,这里暂时不提后面再谈。博主将为各位入门java保驾护航,各位只管冲鸭!!!上天是公平的,只要不辜负时间,时间自然不会辜负你。 何谓学习?博主所理解的学习,它
程序员必须掌握的核心算法有哪些?
由于我之前一直强调数据结构以及算法学习的重要性,所以就有一些读者经常问我,数据结构与算法应该要学习到哪个程度呢?,说实话,这个问题我不知道要怎么回答你,主要取决于你想学习到哪些程度,不过针对这个问题,我稍微总结一下我学过的算法知识点,以及我觉得值得学习的算法。这些算法与数据结构的学习大多数是零散的,并没有一本把他们全部覆盖的书籍。下面是我觉得值得学习的一些算法以及数据结构,当然,我也会整理一些看过
大学四年自学走来,这些私藏的实用工具/学习网站我贡献出来了
大学四年,看课本是不可能一直看课本的了,对于学习,特别是自学,善于搜索网上的一些资源来辅助,还是非常有必要的,下面我就把这几年私藏的各种资源,网站贡献出来给你们。主要有:电子书搜索、实用工具、在线视频学习网站、非视频学习网站、软件下载、面试/求职必备网站。 注意:文中提到的所有资源,文末我都给你整理好了,你们只管拿去,如果觉得不错,转发、分享就是最大的支持了。 一、电子书搜索 对于大部分程序员...
linux系列之常用运维命令整理笔录
本博客记录工作中需要的linux运维命令,大学时候开始接触linux,会一些基本操作,可是都没有整理起来,加上是做开发,不做运维,有些命令忘记了,所以现在整理成博客,当然vi,文件操作等就不介绍了,慢慢积累一些其它拓展的命令,博客不定时更新 顺便拉下票,我在参加csdn博客之星竞选,欢迎投票支持,每个QQ或者微信每天都可以投5票,扫二维码即可,http://m234140.nofollow.ax.
比特币原理详解
一、什么是比特币 比特币是一种电子货币,是一种基于密码学的货币,在2008年11月1日由中本聪发表比特币白皮书,文中提出了一种去中心化的电子记账系统,我们平时的电子现金是银行来记账,因为银行的背后是国家信用。去中心化电子记账系统是参与者共同记账。比特币可以防止主权危机、信用风险。其好处不多做赘述,这一层面介绍的文章很多,本文主要从更深层的技术原理角度进行介绍。 二、问题引入 假设现有4个人...
Python 基础(一):入门必备知识
目录1 标识符2 关键字3 引号4 编码5 输入输出6 缩进7 多行8 注释9 数据类型10 运算符10.1 常用运算符10.2 运算符优先级 1 标识符 标识符是编程时使用的名字,用于给变量、函数、语句块等命名,Python 中标识符由字母、数字、下划线组成,不能以数字开头,区分大小写。 以下划线开头的标识符有特殊含义,单下划线开头的标识符,如:_xxx ,表示不能直接访问的类属性,需通过类提供
这30个CSS选择器,你必须熟记(上)
关注前端达人,与你共同进步CSS的魅力就是让我们前端工程师像设计师一样进行网页的设计,我们能轻而易举的改变颜色、布局、制作出漂亮的影音效果等等,我们只需要改几行代码,不需...
国产开源API网关项目进入Apache孵化器:APISIX
点击蓝色“程序猿DD”关注我回复“资源”获取独家整理的学习资料!近日,又有一个开源项目加入了这个Java开源界大名鼎鼎的Apache基金会,开始进行孵化器。项目名称:AP...
程序员接私活怎样防止做完了不给钱?
首先跟大家说明一点,我们做 IT 类的外包开发,是非标品开发,所以很有可能在开发过程中会有这样那样的需求修改,而这种需求修改很容易造成扯皮,进而影响到费用支付,甚至出现做完了项目收不到钱的情况。 那么,怎么保证自己的薪酬安全呢? 我们在开工前,一定要做好一些证据方面的准备(也就是“讨薪”的理论依据),这其中最重要的就是需求文档和验收标准。一定要让需求方提供这两个文档资料作为开发的基础。之后开发
网页实现一个简单的音乐播放器(大佬别看。(⊙﹏⊙))
今天闲着无事,就想写点东西。然后听了下歌,就打算写个播放器。 于是乎用h5 audio的加上js简单的播放器完工了。 欢迎 改进 留言。 演示地点跳到演示地点 html代码如下`&lt;!DOCTYPE html&gt; &lt;html&gt; &lt;head&gt; &lt;title&gt;music&lt;/title&gt; &lt;meta charset="utf-8"&gt
Python十大装B语法
Python 是一种代表简单思想的语言,其语法相对简单,很容易上手。不过,如果就此小视 Python 语法的精妙和深邃,那就大错特错了。本文精心筛选了最能展现 Python 语法之精妙的十个知识点,并附上详细的实例代码。如能在实战中融会贯通、灵活使用,必将使代码更为精炼、高效,同时也会极大提升代码B格,使之看上去更老练,读起来更优雅。 1. for - else 什么?不是 if 和 else 才
数据库优化 - SQL优化
前面一篇文章从实例的角度进行数据库优化,通过配置一些参数让数据库性能达到最优。但是一些“不好”的SQL也会导致数据库查询变慢,影响业务流程。本文从SQL角度进行数据库优化,提升SQL运行效率。 判断问题SQL 判断SQL是否有问题时可以通过两个表象进行判断: 系统级别表象 CPU消耗严重 IO等待严重 页面响应时间过长
2019年11月中国大陆编程语言排行榜
2019年11月2日,我统计了某招聘网站,获得有效程序员招聘数据9万条。针对招聘信息,提取编程语言关键字,并统计如下: 编程语言比例 rank pl_ percentage 1 java 33.62% 2 c/c++ 16.42% 3 c_sharp 12.82% 4 javascript 12.31% 5 python 7.93% 6 go 7.25% 7
通俗易懂地给女朋友讲:线程池的内部原理
餐厅的约会 餐盘在灯光的照耀下格外晶莹洁白,女朋友拿起红酒杯轻轻地抿了一小口,对我说:“经常听你说线程池,到底线程池到底是个什么原理?”我楞了一下,心里想女朋友今天是怎么了,怎么突然问出这么专业的问题,但做为一个专业人士在女朋友面前也不能露怯啊,想了一下便说:“我先给你讲讲我前同事老王的故事吧!” 大龄程序员老王 老王是一个已经北漂十多年的程序员,岁数大了,加班加不动了,升迁也无望,于是拿着手里
经典算法(5)杨辉三角
杨辉三角 是经典算法,这篇博客对它的算法思想进行了讲解,并有完整的代码实现。
编写Spring MVC控制器的14个技巧
本期目录 1.使用@Controller构造型 2.实现控制器接口 3.扩展AbstractController类 4.为处理程序方法指定URL映射 5.为处理程序方法指定HTTP请求方法 6.将请求参数映射到处理程序方法 7.返回模型和视图 8.将对象放入模型 9.处理程序方法中的重定向 10.处理表格提交和表格验证 11.处理文件上传 12.在控制器中自动装配业务类 ...
腾讯算法面试题:64匹马8个跑道需要多少轮才能选出最快的四匹?
昨天,有网友私信我,说去阿里面试,彻底的被打击到了。问了为什么网上大量使用ThreadLocal的源码都会加上private static?他被难住了,因为他从来都没有考虑过这个问题。无独有偶,今天笔者又发现有网友吐槽了一道腾讯的面试题,我们一起来看看。 腾讯算法面试题:64匹马8个跑道需要多少轮才能选出最快的四匹? 在互联网职场论坛,一名程序员发帖求助到。二面腾讯,其中一个算法题:64匹
面试官:你连RESTful都不知道我怎么敢要你?
面试官:了解RESTful吗? 我:听说过。 面试官:那什么是RESTful? 我:就是用起来很规范,挺好的 面试官:是RESTful挺好的,还是自我感觉挺好的 我:都挺好的。 面试官:… 把门关上。 我:… 要干嘛?先关上再说。 面试官:我说出去把门关上。 我:what ?,夺门而去 文章目录01 前言02 RESTful的来源03 RESTful6大原则1. C-S架构2. 无状态3.统一的接
求小姐姐抠图竟遭白眼?痛定思痛,我决定用 Python 自力更生!
点击蓝色“Python空间”关注我丫加个“星标”,每天一起快乐的学习大家好,我是 Rocky0429,一个刚恰完午饭,正在用刷网页浪费生命的蒟蒻...一堆堆无聊八卦信息的网页内容慢慢使我的双眼模糊,一个哈欠打出了三斤老泪,就在此时我看到了一张图片:是谁!是谁把我女朋友的照片放出来的!awsl!太好看了叭...等等,那个背景上的一堆鬼画符是什么鬼?!真是看不下去!叔叔婶婶能忍,隔壁老王的三姨妈的四表...
为啥国人偏爱Mybatis,而老外喜欢Hibernate/JPA呢?
关于SQL和ORM的争论,永远都不会终止,我也一直在思考这个问题。昨天又跟群里的小伙伴进行了一番讨论,感触还是有一些,于是就有了今天这篇文。 声明:本文不会下关于Mybatis和JPA两个持久层框架哪个更好这样的结论。只是摆事实,讲道理,所以,请各位看官勿喷。 一、事件起因 关于Mybatis和JPA孰优孰劣的问题,争论已经很多年了。一直也没有结论,毕竟每个人的喜好和习惯是大不相同的。我也看
SQL-小白最佳入门sql查询一
不要偷偷的查询我的个人资料,即使你再喜欢我,也不要这样,真的不好;
项目中的if else太多了,该怎么重构?
介绍 最近跟着公司的大佬开发了一款IM系统,类似QQ和微信哈,就是聊天软件。我们有一部分业务逻辑是这样的 if (msgType = "文本") { // dosomething } else if(msgType = "图片") { // doshomething } else if(msgType = "视频") { // doshomething } else { // doshom...
致 Python 初学者
欢迎来到“Python进阶”专栏!来到这里的每一位同学,应该大致上学习了很多 Python 的基础知识,正在努力成长的过程中。在此期间,一定遇到了很多的困惑,对未来的学习方向感到迷茫。我非常理解你们所面临的处境。我从2007年开始接触 python 这门编程语言,从2009年开始单一使用 python 应对所有的开发工作,直至今天。回顾自己的学习过程,也曾经遇到过无数的困难,也曾经迷茫过、困惑过。开办这个专栏,正是为了帮助像我当年一样困惑的 Python 初学者走出困境、快速成长。希望我的经验能真正帮到你
“狗屁不通文章生成器”登顶GitHub热榜,分分钟写出万字形式主义大作
一、垃圾文字生成器介绍 最近在浏览GitHub的时候,发现了这样一个骨骼清奇的雷人项目,而且热度还特别高。 项目中文名:狗屁不通文章生成器 项目英文名:BullshitGenerator 根据作者的介绍,他是偶尔需要一些中文文字用于GUI开发时测试文本渲染,因此开发了这个废话生成器。但由于生成的废话实在是太过富于哲理,所以最近已经被小伙伴们给玩坏了。 他的文风可能是这样的: 你发现,...
程序员:我终于知道post和get的区别
是一个老生常谈的话题,然而随着不断的学习,对于以前的认识有很多误区,所以还是需要不断地总结的,学而时习之,不亦说乎
《程序人生》系列-这个程序员只用了20行代码就拿了冠军
你知道的越多,你不知道的越多 点赞再看,养成习惯GitHub上已经开源https://github.com/JavaFamily,有一线大厂面试点脑图,欢迎Star和完善 前言 这一期不算《吊打面试官》系列的,所有没前言我直接开始。 絮叨 本来应该是没有这期的,看过我上期的小伙伴应该是知道的嘛,双十一比较忙嘛,要值班又要去帮忙拍摄年会的视频素材,还得搞个程序员一天的Vlog,还要写BU...
加快推动区块链技术和产业创新发展,2019可信区块链峰会在京召开
11月8日,由中国信息通信研究院、中国通信标准化协会、中国互联网协会、可信区块链推进计划联合主办,科技行者协办的2019可信区块链峰会将在北京悠唐皇冠假日酒店开幕。   区块链技术被认为是继蒸汽机、电力、互联网之后,下一代颠覆性的核心技术。如果说蒸汽机释放了人类的生产力,电力解决了人类基本的生活需求,互联网彻底改变了信息传递的方式,区块链作为构造信任的技术有重要的价值。   1...
相关热词 c#处理浮点数 c# 生成字母数字随机数 c# 动态曲线 控件 c# oracle 开发 c#选择字体大小的控件 c# usb 批量传输 c#10进制转8进制 c#转base64 c# 科学计算 c#下拉列表获取串口
立即提问