dream890110 2015-03-03 07:09
浏览 175
已采纳

preg_replace_callback仅替换第一次出现

I have the regex to find all numbers with percentage (100|\d\d|\d)\% - this regex is given and I am not allowed to change it. I have input string:

Lorem ipsum 10% dolor, 8%sit amet 50%

I need then to highligh (with HTML tags) parts of string according to that regex so I'd get

Lorem ipsum <i>10%</i> dolor, <i>8%</i>sit amet <i>50%</i> 

Because preg_replace would work only with regex like (100%|\d\d%|\d%) otherwise it would highlight only numbers 0-100. I am using preg_replace_callback like this:

<?php
    $string = "Lorem ipsum 10% dolor, 8%sit amet 50%";
      $count = 0;
        function foo($matches){
            global $count;
            return "<i>".$matches[$count++]."</i>";

        }
        $reg = "/(100|\d\d|\d)\%/";
        $str_out = preg_replace_callback($reg, "foo", $string, PREG_PATTERN_ORDER);
?>

The output is this though:

Lorem ipsum <i>10%</i> dolor, 8%sit amet 50%

Only first occurence is replaced.

  • 写回答

1条回答 默认 最新

  • dongshao4207 2015-03-03 07:12
    关注

    You can use preg_replace also:

    $reg = '/(100|\d\d|\d)%/';
    $repl = preg_replace( $reg, '<i>$0</i>', $input);
    

    RegEx Demo

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
编辑
预览

报告相同问题?

手机看
程序员都在用的中文IT技术交流社区

程序员都在用的中文IT技术交流社区

专业的中文 IT 技术社区,与千万技术人共成长

专业的中文 IT 技术社区,与千万技术人共成长

关注【CSDN】视频号,行业资讯、技术分享精彩不断,直播好礼送不停!

关注【CSDN】视频号,行业资讯、技术分享精彩不断,直播好礼送不停!

客服 返回
顶部