break为啥会有多次循环结果

Question

python使用break后程序还是没有直接退出，循环了好几次，为啥没有直接退出

import datetime
import time
from selenium import webdriver
from selenium.webdriver.common.by import By

driver = webdriver.Edge()
#driver.get("https://www.taobao.com/")
time.sleep(3)
#driver.maximize_window()   #全屏展示
times = '2022-08-23 11:58:00'
#driver.find_element(By.LINK_TEXT,"登录").click()
#print(f"请扫码")
driver.get("https://cart.taobao.com/cart.htm")
time.sleep(20)

while 1==1:
    if driver.find_element(By.ID,"J_SelectAll1"):
        driver.find_element(By.ID, "J_SelectAll1").click()
        break

while 1==1:
    #获取电脑现在时间
    now = datetime.datetime.now().strftime('%Y-%m-%d %H:%M:%S.%f')
    #对比时间，时间到的话就点结算
    #print(now)
    #判断是不是到了秒杀时间？
    if now > times:
        #点击结算
        while 1==1:
            try:
                if driver.find_element(By.ID, "J_Go"):
                    i = 1
                    #print("here")
                    driver.find_element(By.ID, "J_Go").click()
                    #print(f"结算提交成功，我已帮你抢到商品啦，请及时支付订单")
                    print(now)
                    #time.sleep(10)
                    if driver.find_element(By.LINK_TEXT,"提交订单"):
                        print(now)
                        driver.find_element(By.LINK_TEXT,"提交订单").click()
                        break
            except:
                pass

结果如下：
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213
2022-08-23 11:58:00.012213

Process finished with exit code -1

break之后应该直接退出内层循环，我想要只打印一次结算成功和结算的当前时间，希望浅帮个忙，看下为啥会使用break还会多次循环。

Answer 1

重新用代码块或者截图发下代码，这样都看不了缩进