PHP如果速记

Question

I would like to a simple if shorthand that check if an array has a particular key and if so unset it.

$test = array("hi" => "123");
isset($test["hi"]) ? unset($test["hi"]);

Why does this give a parse error? What is the correct syntax.

Answer 1

Because it is a ternary operator. This code:

$a = ($condition)? $b : $c;

is equivalent to:

if($condition) $a = $b;
else $a = $c;

For what you ask, there is no need for a check, you can simply unset() the array element without first checking it, and it would give no error messages:

unset($test["hi"]);