drztpx8735 2011-07-06 16:21
浏览 91
已采纳

当RSS源生成器遇到错误时,它应该返回什么?

I have a PHP script that generates an RSS feed using some external data it retrieves. However, due to the nature of this data, there may be times when it cannot be retrieved or when it receives corrupted data.

What should the PHP script return to the client? Should it return an HTML document with the error message, or should it return a feed with one item that contains the error message?

How would standard feed readers react to receiving an HTML document instead of a feed?

  • 写回答

1条回答 默认 最新

  • dpblwmh5218 2011-07-06 16:26
    关注

    It should return a HTML page with a HTTP status code in the 500s. The user can look at the raw page if they want to understand what the issue is.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 有了解d3和topogram.js库的吗?有偿请教
  • ¥100 任意维数的K均值聚类
  • ¥15 stamps做sbas-insar,时序沉降图怎么画
  • ¥15 unity第一人称射击小游戏,有demo,在原脚本的基础上进行修改以达到要求
  • ¥15 买了个传感器,根据商家发的代码和步骤使用但是代码报错了不会改,有没有人可以看看
  • ¥15 关于#Java#的问题,如何解决?
  • ¥15 加热介质是液体,换热器壳侧导热系数和总的导热系数怎么算
  • ¥100 嵌入式系统基于PIC16F882和热敏电阻的数字温度计
  • ¥15 cmd cl 0x000007b
  • ¥20 BAPI_PR_CHANGE how to add account assignment information for service line