PHP：preg_replace文件路径

Question

I'm stuggeling with this regular expression:

preg_replace('/\/[\s\S]+?_/', '/', $currentFile)

It changes this: /public_html/ftp/Products/1010_Air+Cooled+Condenser/productsheet_Rotary+Drum+Dryer+BR.pdf

To this: html/Air+Cooled+Condenser/Rotary+Drum+Dryer+BR.pdf

Expected result: /public_html/ftp/Products/Air+Cooled+Condenser/Rotary+Drum+Dryer+BR.pdf

"/productsheet_" could also be "/fish-cb_" or "/appeltaartenbakker_"

"/1010_" is always a number with this length.

Answer 1

I believe you are looking for

'~(?!^)/[^/]+_~'

See the regex demo. If you need to make it stop before the first _, add the underscore to the [...]: '~(?!^)/[^_/]+_~'.

Details

• (?!^) - not at the start of the string
• / - a / char (no need to escape as I am using ~ as a regex delimiter char)
• [^/]+ - 1 or more chars other than /
• _ - a _ char.

PHP demo:

$str = '/public_html/ftp/Products/1010_Air+Cooled+Condenser/productsheet_Rotary+Drum+Dryer+BR.pdf';
$result = preg_replace('~(?!^)/[^/]+_~', '/', $str);
echo $result; // => /public_html/ftp/Products/Air+Cooled+Condenser/Rotary+Drum+Dryer+BR.pdf