用于创建多个表的MySQL语法

Question

I am having a some problem that i don’t understand and trying to create tables from a php file , so i created a variable and i added all the create statements in it so i can run a mysql_query on it , i keep getting an error that there is a syntax problem , so i echo the content of the variable and past it in the sql section at phpmyadmin and it word fine but if i try it from php it gives me an error as :

Error creating table:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CREATE TABLE IF NOT EXISTS Materials ( Id int(11) NOT NULL AUTO_INCREMENT,' at line 9

here is the string in the variable that i run the query on :

   // Create Tables Variable
$Tables = "";

// Create Students Table
$Tables = $Tables . "CREATE TABLE IF NOT EXISTS `Students` (
  `Id` int(11) NOT NULL AUTO_INCREMENT,
  `FirstName` varchar(50) DEFAULT NULL,
  `LastName` varchar(50) DEFAULT NULL,
  `Age` int(3) DEFAULT NULL,
  `Major` varchar(50) DEFAULT NULL,
  `Image` varchar(100) DEFAULT NULL,
  PRIMARY KEY (`Id`)
);";

// Create Materials Table
$Tables = $Tables . "CREATE TABLE IF NOT EXISTS `Materials` (
  `Id` int(11) NOT NULL AUTO_INCREMENT,
  `Name` varchar(50) DEFAULT NULL,
  `LastName` varchar(50) DEFAULT NULL,
  PRIMARY KEY (`Id`)
);";

// Create Materials Students intersectons table for many to many relation
$Tables = $Tables . "CREATE TABLE `Material_Student`(
    `Student_Id` INT NOT NULL,  
    `Material_id` INT NOT NULL,    
    FOREIGN KEY (`Student_Id`) REFERENCES Students(`id`) ON UPDATE CASCADE,  
    FOREIGN KEY (`Material_id`) REFERENCES Materials(`id`) ON UPDATE CASCADE
);";

// Create Pages Table
$Tables = $Tables . "CREATE TABLE `Pages`(
    `Id` INT NOT NULL AUTO_INCREMENT,
    PRIMARY KEY(`Id`),
    `Name` varchar(50),
    `Conent` varchar(5000)

);";

// Create News Table
$Tables = $Tables . "CREATE TABLE `News`(
    `Id` INT NOT NULL AUTO_INCREMENT,
    PRIMARY KEY(`Id`),
    `Title` varchar(50),
    `Conent` varchar(5000),
    `Image` varchar(100)
);";

// Create Notifications Table
$Tables = $Tables . "CREATE TABLE `Notifications`(
    `Id` INT NOT NULL AUTO_INCREMENT,
    PRIMARY KEY(`Id`),
    `Title` varchar(50),
    `Conent` varchar(5000),
    `Student_Id` INT NOT NULL,  
    FOREIGN KEY (`Student_Id`) REFERENCES Students(`id`) ON UPDATE CASCADE
);";

so what am I missing here ??

Answer 1

In usual way you cannot execute many queries, I would recommend to execute all of them like different queries, however MySQLi has an option to execute many queries at once, documentation and examples you can find here.