douyanxing6054 2011-04-07 18:10 采纳率: 0%
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Symfony问题:如何获取/读取页面的HTML内容?

So, I have a actions.class.php and have the function like that:

public function executeGetHTML($request)
{
   $pageName = $request->getParameter('name', '');
}

I do not want to output the content of getHTMLSuccess.php

instead, depending on the request, I need to get the HTML code of another page (without processing it ..e.g. filtering it..etc). Actually, the page content will be output in JSONP within a JSON variable. e.g.

For example, I call /getHTML?name=abc

and abc.html (or abc.php) has the content:

<div>Hello, my beautiful world</div>

then I will get the page content of Hello, my beautiful world

and output it as: mycallback({content:'Hello, my beautiful world'});

I know I can do file_get_content(...) but it sounds like very heavy to do file read explicitly while symfony should already cache and know .

include / require won't work in this... so, is there a light-weight way to do it?

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  • dongtiaozhou4914 2011-04-13 11:57
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    You could try the getPresentationFor method (http://www.symfony-project.org/api/1_4/sfController#method_getpresentationfor)

    public function executeGetHTML($request) {
      $pageName = $request->getParameter('name', '');
    
      $html = $this->getPresentationFor('module', 'action');
    }
    

    This will return the output for the requested module/action rather than outputing it to screen

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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