c＋＋：求1000以内可以同时被9和10整除的所有数，要求一行输出5个数据

Question

#include
using namespace std;
int main()
{
int i=1, m;
m = 0;

for ( i; i < 1000; i++)
{
    if
        (i % 9 == 0 && i % 11 == 0)
        
        break;
    m = m + 1;
    if (m % 5 == 0)
        cout << m << endl;
    

}
return 0;
}

Answer 1

#include<iostream>
using namespace std;
int main()
{
    int i=1, m;
    m = 0;
    for ( i; i <= 1000; i++)
    {
        if(i % 10 == 0 && i % 9 == 0){
            m = m + 1;
            if (m % 5 == 0)
                cout << i << endl;
            else
                cout << i << " "; 
            }
    }
    return 0; 
}