douan7529 2016-02-04 22:02
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I know I can do this without the alias, but in this case trying to instantiate the object using an alias attempts to find a class by the alias name. Can this not be done in PHP?

// Import of manager, admin, etc login PageObjects
use Page\Acceptance\Users\Login as ManagerLoginPage;
use Page\Acceptance\Admins\Login as AdminLoginPage;


// Login user type snippet
$alias= $userType . 'LoginPage'; // produces ManagerLoginPage
$User = new $alias($this); // tries to instantiate a class named 'ManagerLoginPage', which doesn't exist

$User->{'loginAs' . $userType}($user);
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  • doubi1797 2016-02-04 22:10

    As the documentation explains:

    The ability to refer to an external fully qualified name with an alias, or importing, is an important feature of namespaces. This is similar to the ability of unix-based filesystems to create symbolic links to a file or to a directory.

    And several paragraphs below:

    Importing is performed at compile-time, and so does not affect dynamic class, function or constant names.

    This means that when you write:

    use Page\Acceptance\Users\Login as ManagerLoginPage;
    $page = new ManagerLoginPage();

    PHP expands the aliases during the compilation to:

    $page = new \Page\Acceptance\Users\Login();

    You have to put the complete class name (including all the containing namespaces) into the variable $alias to make it work:

    $alias = 'Page\Acceptance\Users\Login';
    $User = new $alias($this);
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
  • dongzheng4556 2016-02-04 22:16

    You can use:

    $alias = $userType . 'LoginPage';
    class_alias('Page\Acceptance\Users\Login', $alias);
    $User = new $alias();



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