C语言基础编程求解答7-5

Question

#include<stdio.h>
#include<math.h>
int main()
{
    int a,b,c,disc;
    double x1,x2,p,q;
    scanf("%d %d %d",&a,&b,&c);
    disc=b*b-4*a*c;
    p=-b/(2.0*a);
    q=sqrt(disc)/(2.0*a);
    x1=p+q;
    x2=P-q;
    if(disc>=0)
    {
        if(x1<=x2)
            printf("%.2lf %.2lf",x1,x2);
        else
            printf("%.2lf %.2lf",x2,x1);
     }
    if(disc<0)
        printf("-1 -1");
    return 0;
}

错在哪里了
求解答

Answer 1

#include <stdio.h>
#include <math.h>
int main()
{
double a,b,c;
scanf("%lf %lf %lf",&a,&b,&c);
double x;
x=bb-4a*c;
if(a==0&&b==0&&c==0){
printf("Zero Equation\n");
}else if(a==0&&b==0&&c!=0){
printf("Not An Equation\n");
}else if(a==0&&b!=0){
printf("%.2f\n",-c/b);
}else if(x==0){
printf("%.2f\n",-b/2/a);
}else if(x>0){
printf("%.2f\n%.2f\n",(-b+sqrt(x))/2/a,(-b-sqrt(x))/2/a);
}else{
if(b==0){
printf("0.00+%.2fi\n0.00-%.2fi\n",sqrt(-x)/2/a,sqrt(-x)/2/a);
}else
printf("%.2f+%.2fi\n%.2f-%.2fi\n",-b/2/a,sqrt(-x)/2/a,-b/2/a,sqrt(-x)/2/a);
}
return 0;
}