输出第一个数组的值后 数组后面几个数莫名改变了

Question

问题遇到的现象和发生背景

输出第一个数组的值后 数组后面几个数莫名改变了

用代码块功能插入代码，请勿粘贴截图

#include<stdio.h>

#define Gain 6.3168e-3
#define Offset -31.58423

double* Radiation(int* a);

int main()
{
    int dn[] = { 100,120,50,100,100,90,120,90,100,100,50,50,50,50,8,105,110,110,50,110,105,110,110,100,100 };
    double *re;
    re = Radiation(dn);
    for (int i = 0; i < 25; i++)
    {
        printf("%f\t", re[i]);
        if ((i + 1) % 5 == 0)
        {
            printf("\n");
        }
    }
    return 0;
}

double* Radiation(int* a)
{
    double b[25];
    for (int i = 0; i < 25; i++)
    {
        b[i] = Gain * a[i] + Offset;
    }
    return b;
}

运行结果及报错内容

我的解答思路和尝试过的方法

自己在监视窗口看了一下，本来都是有正确值的，在re[0]输出后，立刻就变了，实在不理解为什么，问问大家

Answer 1

将 double b[25]; 静态数组改为动态的吧，就解决问题了，供参考：

#include <stdio.h>
#include <stdlib.h>
#define Gain 6.3168e-3
#define Offset -31.58423
 
double* Radiation(int* a);
 
int main()
{
    int dn[] = { 100,120,50,100,100,90,120,90,100,100,50,50,50,50,8,105,110,110,50,110,105,110,110,100,100 };
    double *re;
    re = Radiation(dn);
    for (int i = 0; i < 25; i++)
    {
        printf("%f\t", re[i]);
        if ((i + 1) % 5 == 0)
        {
            printf("\n");
        }
    }
    return 0;
}
 
double* Radiation(int* a)
{
    //double b[25];
    double *b = (double *)malloc(sizeof(double)* 25);
    for (int i = 0; i < 25; i++)
    {
        b[i] = Gain * a[i] + Offset;
    }
    return b;
}