duanhong1985 2012-06-20 01:10
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jQuery $ .post()函数难以显示结果?

I am using jQuery's $.post function to retrieve some data from a php file, but the returned data does not seem to be showing? Here is what I have got.

Javascript Code:

$(document).ready(function(){
$("#import").click(function(){
        //This code works when uncommented, used for debugging.
        /*var x = "tester";
        $('input[name=title]').val(x);*/

        $.post("import.php", function(data){
            $('input[name=title]').empty().val(data.name); // John
            $('input[name=subtitle]').empty().val(data.time); //  2pm
            }, "json");
    });
});

PHP import.php Code:

<?php
    $my_array = array("name"=>"John","time"=>"2pm");
    echo json_encode($my_array); 
?>

Is there something silly I've missed out, or have I gone about this incorrectly. I'm fairly new to javascript/jquery.

  • 写回答

1条回答 默认 最新

  • dpfqy5976 2012-06-20 06:54
    关注

    you have to use json.parse() and assign it to a variable to use it as an object.

    download json2.js from here

    json.parse has this documentation.

    a request type of JSON does not mean the ajax function returns the "data" value as an object. it is still a string and needs to be parsed with

    var myObject = JSON.parse(data);
    

    then you can use it like

    alert(myObject.name);
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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