判断正数有多少 负数有多少 然后计算总和

Question

#include
using namespace std;
int main()
{
int num,a=0,b=0,d;
cout<<"请输入一串整数,如果为0则表明程序结束。"<<endl;
while(1)
{
cin >>num;
if(num>0)a++;
if(num<0)b++;
else break; }
d=a+b;
cout << "正数个数为：" <<a<<'\n'<<"负数个数为："<<b<<'\n'<<"他们之和为:"<<d;
return 0;
}

Answer 1

a和b代表的是正负数的数量，又不是和。你加他们有啥用

#include <iostream>
using namespace std;
int main()
{
int num,a=0,b=0,sum=0;
cout<<"请输入一串整数,如果为0则表明程序结束。"<<endl;
while(1)
{
    cin >>num;
    if(num>0)
        a++;
    else if(num<0)
         b++;
    else 
          break; 
    sum += num;
}
cout << "正数个数为：" <<a<<endl<<"负数个数为："<<b<<endl<<"他们之和为:"<<sum;
return 0;
}