我在网上搜到的是使用节约算法计算的只是材料运输产生的碳排放量
clc
clear all
p1=0.9;
customer=xlsread('customer.xlsx'); %需求点信息
facility=xlsread('facility.xlsx'); %设施点信息
facilityposition=facility(:,2:3); %设施坐标
customerposition=customer(:,2:3); %需求点坐标
position=[facilityposition;customerposition];
xlswrite('position.xlsx',position)
position1=[position(:,1) position(:,2)];
distMatrix=dists(position1); %计算得出的两点之间的距离
xlswrite('distMatrix.xlsx',distMatrix)
ttimeu=fix(distMatrix); %两点之间的距离
%%%%%%%%%%%%%%%%%%%%%%%%%固定数据%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
Qofcar=200; %车辆容量
costofallcar=5000; %车辆固定成本
costofunitdistance=9; %单位距离成本
tanpaifangyinzi=1; %车辆碳排放因子
danweiyouhao=1; %车辆单位油耗
%%%%%%%%%%%%%%%%%%%%%%%计算出来的数据%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
Numberofpoints=size(customer,1); %需求点数量
Numberoffacilities=size(facility,1); %设施点数量
quantity=[customer(:,1) customer(:,4) customer(:,4)]; %需求点需求量
Qoffacilities=[facility(:,1) facility(:,4)]; %设施容量
timewindow=[customer(:,1) customer(:,6:7)]; %需求点时间窗
countfacility=facility(:,5); %建立设施固定成本
codeofpicture=1;
timewindow
assignofpoint=[2 1 2 1 3 3 1 2 1 1 2 3 2];
[outcome1,outcome2,outcome3]=cw(Numberoffacilities,assignofpoint,ttimeu,timewindow,distMatrix,quantity,Qofcar,p1);
%outcome1=[1 1 2 1 2 3 3 4 4 3 5 5 5];
%outcome2=[9 2 10 4 7 13 1 11 8 3 12 5 6];
[outcome1,outcome2,outcome3]=tabu(outcome1,outcome2,outcome3,distMatrix,ttimeu,Numberoffacilities,timewindow);
[Picture]=picture(codeofpicture,outcome1,outcome2,outcome3,customer,facility);
function [outcome1,outcome2,outcome3]=cw(Numberoffacilities,assignofpoint,ttimeu,timewindow,distMatrix,quantity,Qofcar,p1)
H=1;
outcome3=zeros(1,Numberoffacilities);%与设施点的伪编号是一一对应的
%%%%%%%找到实际分配的设施点，因为之前的chrom中为1的点，可能%%%%%%%%%%%%%
facilitypop=zeros(1:Numberoffacilities);
facilitypop(assignofpoint)=1;
trueSelectefacilities=find(facilitypop(1,:)==1); %被选择的设施编号
trueselectNumberoffacilities=size(trueSelectefacilities,2);
outcome1=cell(1,trueselectNumberoffacilities);
outcome2=cell(1,trueselectNumberoffacilities);
for i=1:trueselectNumberoffacilities%此时的设施为i
a=trueSelectefacilities(i);%设施的伪编号
pointofsubroute=find(assignofpoint==a);%属于该设施点的所有需求点的伪编号
Numberofpointsofsubroute=size(pointofsubroute,2);%该设施点的需求点数量
judge=zeros(1,Numberofpointsofsubroute); %判断需求点的位置情况
chrom1=zeros(1,Numberofpointsofsubroute);%最后输入的是伪编号
chrom2=sort(pointofsubroute); %需求点伪编号从小到大排序
originalchrom2=chrom2;
%%对关键节点先分配一个车辆给它？？？？？？？？？？？？？？？？？？？？？对不对？
%for j=1:Numberofpointsofsubroute
%if timewindow(chrom2(j),2)==timewindow(chrom2(j),3)
%chrom1(j)=H;
%H=H+1;
%end
%end
%%%%%%%%计算到达时间%%%%%%%%%%%%%%%%%%%%
arrivetime=zeros(1,Numberofpointsofsubroute);%需求点的到达时间,与当前的originalchrom2位置一一对应，与分配给该设施点的需求点一一对应
for j=1:Numberofpointsofsubroute
if ttimeu(chrom2(j)+Numberoffacilities,a)<timewindow(chrom2(j),2)
arrivetime(j)=timewindow(chrom2(j),2);
else
arrivetime(j)=ttimeu(chrom2(j)+Numberoffacilities,a);
end
end
%%%%%%%%%%%%%%%%%%%%%%%%%路径节约值列表%%%%%%%%%%%%%%%%%%%%%%
savingnumber=zeros(Numberofpointsofsubroute);%与分配给该设施的需求点的伪编号一一对应
for j=1:Numberofpointsofsubroute
for z=1:Numberofpointsofsubroute
if j~=z
savingnumber(j,z)=distMatrix(chrom2(j)+Numberoffacilities,a)+distMatrix(chrom2(z)+Numberoffacilities,a)-distMatrix(chrom2(j)+Numberoffacilities,chrom2(z)+Numberoffacilities);
end
end
end
[a b]=max(savingnumber);%a输入值，b中对应的数字为行，对应的列数为列
[c d]=max(a);%c输入具体的当前节约值，d为列数
e=b(d);%e为行
%%%在节约值列表中e行d列是当前最大的节约量
E=chrom2(e);%此时的E为节约量最大的需求点伪编号之一
D=chrom2(d);%此时的D为节约量最大的需求点伪编号之1
done=1;
while(done<2)
if judge(e)==0&&judge(d)==0
PD=0;
a=quantity(E,2)+quantity(D,2);
aa=quantity(E,3)+quantity(D,3);
pp1=normcdf(Qofcar,a,sqrt(aa));
a2=find(chrom2==D);
b2=find(chrom2==E);
if pp1>p1
EFj=arrivetime(e)+ttimeu(E+Numberoffacilities,D+Numberoffacilities)-arrivetime(d);
if EFj<0
aheadtime=arrivetime(d)-timewindow(D,2);
if aheadtime>=-EFj
PD=1;
end
elseif EFj==0
PD=1;
elseif EFj>0
delaytime=timewindow(D,3)-arrivetime(d);
if delaytime>=EFj
PD=1;
end
end
if PD==1
chrom1(e)=H;
chrom1(d)=H;%H为车辆编号
judge(e)=1;%与设施直接相连的起点为1
judge(d)=2;%与设施直接相连的终点为2
H=H+1;
arrivetime(d)=arrivetime(d)+EFj;
if b2>a2
chrom2(a2)=E;
chrom2(b2)=D;
end
end
end
savingnumber(e,d)=0;
elseif judge(e)==0&&judge(d)==1;
a2=find(chrom2==D);
b2=find(chrom2==E);
a=find(chrom1==chrom1(a2));
b=sum(quantity(chrom2(a),2))+quantity(E,2);
bb=sum(quantity(chrom2(a),3))+quantity(E,3);
pp1=normcdf(Qofcar,b,sqrt(bb));
c=size(a,2);
if pp1>p1
EFj=arrivetime(e)+ttimeu(E+Numberoffacilities,D+Numberoffacilities)-arrivetime(d);
if EFj<0
a1=10000;
for j=1:c
b1=find(originalchrom2==chrom2(a(j)));
Aheadtime=arrivetime(b1)-timewindow(chrom2(a(j)),2);
if Aheadtime<a1
aheadtime=Aheadtime;
a1=Aheadtime;
end
end
if aheadtime>=-EFj
PD=1;
end
elseif EFj==0
PD=1;
elseif EFj>0
a1=10000;
for j=1:c
b1=find(originalchrom2==chrom2(a(j)));
Delaytime=timewindow(chrom2(a(j)),3)-arrivetime(b1);
if Delaytime<a1
delaytime=Delaytime;
a1=Delaytime;
end
end
