dounang1974 2010-10-30 11:14
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PHP while循环省略了MySQL数据库选择的第一个条目

I have four rows in my table. Only three are shown.

$query  = "SELECT * FROM table";
$result = mysql_query($query);
$row    = mysql_fetch_array($result);

while($row = mysql_fetch_array($result)) {
    echo $row['id'];
}

The result is 234, but should be 1234.

What am I doing wrong?

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  • dongzi0850 2010-10-30 11:17
    关注
    $row    = mysql_fetch_array($result);
    

    This line already fetches the first entry. Thus in the while loop you fetch the second element.

    Correctly it should be:

    $query  = "SELECT * FROM table";
    $result = mysql_query($query);
    
    while ($row = mysql_fetch_array($result)) {
        echo $row['id'];
    }
    

    Alternatively:

    $query  = "SELECT * FROM table";
    $result = mysql_query($query);
    $row    = mysql_fetch_array($result);
    
    do {
        echo $row['id'];
    } while ($row = mysql_fetch_array($result));
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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