编程介的小学生 2019-09-09 18:30 采纳率: 0.4%
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Playground Hideout 怎么实现

Problem Description
Little Timmy likes playgrounds, especially those with complicated constructions of wooden towers interconnected with plank bridges or ropes, with slides and rope-ladders. He could play on his favourite playground for days, if only his parents let him. Sooner or later they decide that it is time to go home. For their next trip to a playground Timmy has a plan: he will not simply let his father grab him, but climb to the highest platform of the most complex structure and hide there. His father will never be able to reach him there or at least it will give Timmy some extra time.
An adventure playground consists of several platforms. The difficulty of reaching a platform directly from ground level varies. In addition the different platforms are interconnected by “bridges” of different difficulty. There are connections that can be used a lot more easily in one direction than in the other, e.g. slides. Given a plan of an adventure playground you need to help Timmy find the platform that is most difficult to reach from ground level. The difficulty for a path in the adventure playground can be estimated as a sum of the difficulties of the connections used. The difficulty of reaching a platform is the difficulty of the least difficult path from ground level to the platform.

Input
The input starts with a line containing a single integer n, the number of test cases. Each test case starts with a line containing two integers 1 <= p, c <= 10000, the number of platforms and connections respectively (we allow for large playgrounds). A line with p integers pi ∈ [0, 1000] follows, where pi is the difficulty of reaching platform i directly from ground-level. The next c lines each describe a connection between two platforms. They consist of four integers i, j, a, b; i < j, the zero-based index of the two connected
platforms and the difficulties a ∈[0, 1000] and b ∈ [0, 1000] of using the connection to get from pi to pj and from pj to pi respectively. There can be multiple connections between any two platforms.

Output
The output for every test case begins with a line containing “Scenario #i:”, where i is the number of the test case counting from 1. Then, output a single line containing the zero-based index of the platform that is most difficult to reach from ground level. If two or more platforms are equally difficult to reach, output the smallest index of among those platforms. Terminate each test case with an empty line.

Sample Input
2
4 3
1 10 10 40
0 3 3 2
1 3 4 3
2 3 5 4
2 2
11 10
0 1 2 2
0 1 1 0

Sample Output
Scenario #1:
2

Scenario #2:
0

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  • 你知我知皆知 2024-07-30 21:55
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    以下回答参考 皆我百晓生券券喵儿 等免费微信小程序相关内容作答,并由本人整理回复。

    # Sample Code
    
    ## Function to calculate the difficulty of reaching a given platform
    calculate_difficulty <- function(platforms, connections) {
      # Create a matrix to store the difficulty of reaching each platform from ground level
      difficulty_matrix <- matrix(NA, nrow = length(platforms), ncol = length(connections))
      
      # Initialize the first row of the difficulty matrix with the difficulty of reaching each platform directly from ground level
      for (i in 1:length(platforms)) {
        difficulty_matrix[i, ] <- platforms[i]
      }
      
      # Calculate the difficulty of each connection and update the difficulty matrix accordingly
      for (i in 1:nrow(difficulty_matrix)) {
        for (j in 1:ncol(difficulty_matrix)) {
          difficulty_matrix[i, j] <- min(difficulty_matrix[(i + 1):nrow(difficulty_matrix), j])
        }
      }
      
      return(difficulty_matrix)
    }
    
    # Function to solve the problem
    solve_playground_hideout <- function() {
      input <- readLines()
      num_cases <- as.integer(gsub(" ", "", input[1]))
      
      for (case_number in 1:num_cases) {
        platforms <- sapply(input[case_number + 2], as.integer)
        connections <- sapply(input[case_number + 3 : case_number + 6], function(x) {
          x <- strsplit(x, " ")[[1]]
          i, j, a, b <- x
          list(i, j, a, b)
        })
        
        difficulty_matrix <- calculate_difficulty(platforms, connections)
        
        max_difficulty_index <- which.max(difficulty_matrix[, 2]) - 1
        
        print(paste("Scenario #", case_number, ":"))
        print(max_difficulty_index)
      }
    }
    
    solve_playground_hideout()
    

    This code defines a calculate_difficulty function that calculates the difficulty of reaching a given platform based on the provided connections, and a solve_playground_hideout function that reads the input data from the sample input file and prints the solution for each test case. The readLines() function is used to read the input data from the sample input file, while the gsub() function is used to remove spaces from the first line of the input file. The as.integer() function is used to convert the input strings into integers.

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