有两种方式可以实现:
1、在form表单action指定后台的地址,按钮用submit即可。
2、使用ajax的进行请求,给一个参考的连接:
<form id="signupForm" autocomplete="off">
<h4 class="no-margins">登录:</h4>
<input type="text" name="username" class="form-control uname" placeholder="用户名" value="admin" />
<input type="password" name="password" class="form-control pword" placeholder="密码" value="admin123" />
<div class="checkbox-custom" th:if="${isRemembered}" th:classappend="${captchaEnabled==false} ? 'm-t'">
<input type="checkbox" id="rememberme" name="rememberme"> <label for="rememberme">记住我</label>
</div>
<button class="btn btn-success btn-block" id="btnSubmit" data-loading="正在验证登录,请稍候...">登录</button>
</form>
function login() {
var username = $.common.trim($("input[name='username']").val());
var password = $.common.trim($("input[name='password']").val());
var validateCode = $("input[name='validateCode']").val();
var rememberMe = $("input[name='rememberme']").is(':checked');
$.ajax({
type: "post",
url: ctx + "login",
data: {
"username": username,
"password": password,
"validateCode": validateCode,
"rememberMe": rememberMe
},
success: function(r) {
if (r.code == web_status.SUCCESS) {
location.href = ctx + 'index';
} else {
$('.imgcode').click();
$(".code").val("");
$.modal.msg(r.msg);
}
}
});
}
这里只是提供一个大致思路啊,代码需要改的