理解一个简单的正则表达式

Question

I am developing a Symfony2 PHP application. In my Wamp server, the application is stored in www/mySite/ and my index.php is www/mySite/web/app_dev.php. Because/ of that, I have URL like 127.0.0.1/mySite/web/app_dev.php

I wanted to change the path so I acces my index file just by typing 127.0.0.1. After some research, I figured out that writting this .htacces in the www folder works :

RewriteEngine on
Rewritecond %{REQUEST_URI} !^/mySite
Rewriterule ^(.*)$ /mySite/web/app_dev.php

The only problem is that I don't understand why. Does somebody explain it to me ? I don't really understand the two last line, and regex like ^(.*)$

Thanks

Answer 1

This is a simple regex indeed:

^(.*)$

Let's break it up:

• ^ - begging of a string
• ( and ) - capture group, used to match part of a string
• . - any character
• .* - any charactery any number of times
• $ - end of a string

So, putting it all together, it means: "match any number of any characters". Later this matched part (part in parentheses) is replaced by /mySite/web/app_dev.php.

To explain regexes a little bit more we could imagine different regexes:

• ^lorem.*$ - string starting with word "lorem" followed by any number of any characters
• ^$ - an empty string
• ^...$ - a string containing three characters.

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Now, putting it all together - Apache's rewrite rules are usually built of two directives: RewriteCond and RewriteRule. The latter directive will affect only those requests which match the condition given in the RewriteCond. You can think of them as a "if-then" pair:

# the "if" part - if request URI does not match ^/mySite
Rewritecond %{REQUEST_URI} !^/mySite

# the "then" part - then rewrite it to "/mySite/web/app_dev.php"
Rewriterule ^(.*)$ /mySite/web/app_dev.php