JAVA8怎么把有微小偏差坐标分组为相同位置

Question

JAVA8怎么实现把有微小偏差坐标分组为相同位置？坐标X和Y都是0.05的偏差就认为多个NPC重叠
[{NPC=强盗, X=0.45, y=0.1}, {NPC=宝箱, X=0.5, y=0.15}

Answer 1

public class Test6 {
    //偏移量x
    private static final double OFFSET_X = 0.05;
    //偏移量y
    private static final double OFFSET_Y = 0.05;

    public static void main(String[] args) {
        NPC npc1=new NPC("海盗",0.45,0.1);
        NPC npc2=new NPC("宝箱",0.5,0.15);
        if(compareTo(npc1,npc2)){
            System.out.println(npc1.getName()+"和"+npc2.getName()+"处在相同的位置");
        }else {
            System.out.println(npc1.getName()+"和"+npc2.getName()+"处在不同的位置");
        }
    }


    private static boolean compareTo(NPC npc1,NPC npc2){
        //精度计算要换成bigDecimal
        BigDecimal x1 = BigDecimal.valueOf(npc1.getX());
        BigDecimal y1 =BigDecimal.valueOf(npc1.getY());
        BigDecimal x2 =BigDecimal.valueOf(npc2.getX());
        BigDecimal y2 =BigDecimal.valueOf(npc2.getY());

        if (!(Math.abs(x1.subtract(x2).doubleValue())==OFFSET_X)) {
            return false;
        }
        if (!(Math.abs(y1.subtract(y2).doubleValue())==OFFSET_Y)) {
            return false;
        }
        return true;
    }

    private static class NPC{
        private String name;
        private double x;
        private double y;

        public NPC(String name, double x, double y) {
            this.name = name;
            this.x = x;
            this.y = y;
        }

        public String getName() {
            return name;
        }

        public void setName(String name) {
            this.name = name;
        }

        public double getX() {
            return x;
        }

        public void setX(float x) {
            this.x = x;
        }

        public double getY() {
            return y;
        }

        public void setY(float y) {
            this.y = y;
        }
    }
}