java如何将json中的list解析出来，并将每一个元素放入arraylist中？

Question

java如何将如图所示的json中的list解析出来，并将每一个元素放入arraylist中？

{"current_time":"2022-11-22T12:22:39.089Z","timelist":["2022-08-31T19:48:58.290Z","2022-11-20T02:20:49.684Z","2022-01-20T02:06:37.952Z","2022-01-09T15:07:15.109Z","2022-02-28T12:48:49.242Z","2022-10-21T00:11:00.437Z","2022-02-10T09:52:45.520Z","2022-07-28T23:44:04.718Z","2022-02-02T01:48:27.967Z","2022-07-14T20:31:48.570Z","2022-05-20T14:20:13.222Z","2022-03-30T13:18:09.986Z"]}

我这种用jsonobject的写法对吗？

private void parseJSONWithJSONObject(String jsonData){
                try{
                    JSONObject jsonObject = new JSONObject(jsonData);
                    JSONArray jsonArray=jsonObject.getJSONArray("timelist");
                    for(int i=0;i<jsonArray.length();i++){
                        JSONObject jsonObject1=jsonArray.getJSONObject(i);
                        String time_n=jsonObject1.getString("");
                        Log.d("timedata",time_n);
                    }
                }catch (Exception e){
                    e.printStackTrace();
                }
            }

Answer 1

本来就是个Array，直接获取值不就好了么

 private void parseJSONWithJSONObject(String jsonData){
        try{
            JSONObject jsonObject = new JSONObject(jsonData);
            JSONArray jsonArray=jsonObject.getJSONArray("timelist");
            for(int i=0;i<jsonArray.length();i++){
                 
                Log.d("timedata",jsonArray.get(i));
            }
        }catch (Exception e){
            e.printStackTrace();
        }
    }