呈现不同的视图脚本，将数据传递到该视图并在Zend中获取输出

Question

I want to render a different view in my action, pass data from action to that view and get its output in a variable.

I know that

  $output = $this->view->render('path/to/script');

render different view script and returns output. But I also want to pass data to this script from my action but not succeeded so far. I have used

 $this->view->data = $data

But it doesn't send data to this script.

Can any one guide how can I do it?

Answer 1

You can pass an array of data to the view script:

$this->view->render('path/to/script/script', array('someValue' => true)); 

Access it in the view script with:

<?= $this->someValue ?>

EDIT: In a controller I always use...

$this->view->assign('someValue', 'data');

EDIT: With layout pattern... You need to set a variable in the controller for the path of the view script you want to use in the layout template and any variables/data you want passing to the view partial.

In controller:

$this->view->assign('partialPath', 'path/to/partial');
$this->view->assign('partialdata', 'value');

In Layout:

$this->view->render($this->partialPath, $this->partialData) //renders partial and passes data

In partial:

<?= $this->partialData ?> // echos data