C语言谁能教我下面的代码怎么打

Question

本人编程初学者，在C语言学习中遇到了困难
请问哪位可以帮我打一下这个代码，今晚十一点前要交

Answer 1

#include <stdio.h>

int str_to_int(char *s)
{
    int n = 0;
    while (*s)
    {
        n = n * 10 + (*s - '0');
        s++;
    }
    return n;
}

int find_int_in_array(int *arr, int l, int n)
{
    for (int i = 0; i < l; i++)
    {
        if (arr[i] == n)
            return i;
    }
    return -1;
}

int main()
{
    char str[100], buf[100];
    int num[100], count[100] = {0}, inx = 0, cnt = 0, i = 0, n, t;
    fgets(str, 100, stdin); // fgets输入末尾会包含\n

    while (1)
    {
        if (str[i] != ' ' && str[i] != '\n')
            buf[inx++] = str[i];

        if ((i > 0 && str[i] == ' ') || str[i] == '\n')
        {
            buf[inx] = '\0';
            n = str_to_int(buf);
            t = find_int_in_array(num, cnt, n);
            if (t == -1)
            {
                num[cnt] = n;
                count[cnt]++;
                cnt++;
            }
            else
                count[t]++;

            inx = 0;
        }
        if (str[i] == '\n')
            break;
        i++;
    }

    for (i = 0; i < cnt; i++)
    {
        printf("%d %d\n", num[i], count[i]);
    }

    scanf("%d", &n);
    t = find_int_in_array(num, cnt, n);
    if (t == -1)
        printf("不存在");
    else
        printf("%d", count[t]);

    return 0;
}