PHP中的选定字段

Question

I have a select box where the user chooses a sex (gender) from a drop down, and their choice is specified with "selected" in the select tag. But the box always ends up 'Choose'. What is wrong in the following syntax?

echo"<select name='sex'>
<option value='N' '". ($info['sex'] == "N" ? 'selected=selected':'') ."'>Choose</option>
<option value='M' '". ($info['sex'] == "M" ? 'selected=selected':'') ."'>Male</option>    
<option value='F' '". ($info['sex'] == "F" ? 'selected=selected':'') ."'>Female</option> 
</select>";

The $info['sex'] is from a consult SQL that return always N, M or F.

Answer 1

Your selected=selected is being quoted and output like

<option value='N' 'selected=selected'>

when you run your code, use this

echo"<select name='sex'>
<option value='N' ". ($info['sex'] == "N" ? 'selected=\'selected\'':'') .">Choose</option>
<option value='M' ". ($info['sex'] == "M" ? 'selected=\'selected\'':'') .">Male</option>    
<option value='F' ". ($info['sex'] == "F" ? 'selected=\'selected\'':'') .">Female</option> 
</select>";

notice the escaped quotes at 'selected=\'selected\'' and the lack of single-quotes at ". ($info['sex'] and .">

demo: http://codepad.org/AX95BzTR

here's a fiddle showing your problematic output: http://jsfiddle.net/JKirchartz/KB4rv