dreamy6301 2010-05-07 18:06
浏览 131
已采纳

PHP - 检查该值是否在数组中没有出现两次

I have a array inside my PHP app that looks like this:

Array
(
    [0] => Array
        (
            [name] => Name1
            [language] => 1
        )

    [1] => Array
        (
            [name] => Name2
            [language] => 1
        )

)

How can I check that "language" with value 1 doesnt appear twice, as effectively as possible?

  • 写回答

2条回答 默认 最新

  • douxie7339 2010-05-07 18:11
    关注
    $dupe = 0;
    foreach($yourarray as $key => $val) {
        if(array_key_exists($seen, $val['language'])) {
            // a duplicate exists!
            $dupe = 1;
            // could do other stuff here too if you want,
            // like if you want to know the $key with the dupe
    
            // if all you care about is whether or not any dupes
            // exist, you could use a "break;" here to early-exit
            // for efficiency. To find all dupes, don't use break.
        }
        $seen[$val['language']] = 1;
    }
    
    // If $dupe still = 0 here, then no duplicates exist.
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥15 什么设备可以研究OFDM的60GHz毫米波信道模型
  • ¥15 不知道是该怎么引用多个函数片段
  • ¥15 爬取1-112页所有帖子的标题但是12页后要登录后才能 我使用selenium模拟登录 账号密码输入后 会报错 不知道怎么弄了
  • ¥30 关于用python写支付宝扫码付异步通知收不到的问题
  • ¥50 vue组件中无法正确接收并处理axios请求
  • ¥15 隐藏系统界面pdf的打印、下载按钮
  • ¥15 基于pso参数优化的LightGBM分类模型
  • ¥15 安装Paddleocr时报错无法解决
  • ¥15 python中transformers可以正常下载,但是没有办法使用pipeline
  • ¥50 分布式追踪trace异常问题