这样也很别扭
const p = new Promise((resolve, reject) => {
getGroupRole({ gr_id: e.id }).then((res) => { // axios
if (res.data.role == 'general.admin') {
warningInfo(t('general.no_permission.admin'))
reject('不是管理员')
}
}) // 外面不套个promise, 仅在这加.then ,又没有reject,
}).then(() => {
console.log('运行到这了')
// ... 继续在这向后端 axios
// teamDetails.value = true
// groupStore.value = e
})
promise.then 我这样写很low,请教方法
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3条回答 默认 最新
CSDN专家-showbo 2022-12-16 09:25关注可以用aysnc+await+Promise来改造下,变成像函数编程一样明了一些
<script> function getGroupRole({ gr_id=null}) { return new Promise((resolve, reject) => { setTimeout(() => { let rnd = Math.random(); console.log(rnd) if (rnd > .5) resolve({ data: { role: Math.random()>.5?'admin': 'general.admin' } }); else reject({ error:'reject' }); }, 1000) }) } function warningInfo(msg) { console.log(msg) } function t(msg) { return msg } //内部用到await语句的函数需要用async来修饰函数 async function business(e) { try { let res = await getGroupRole({ gr_id: e.id }); console.log(res) if (res.data.role == 'general.admin') { warningInfo(t('general.no_permission.admin')) //reject('不是管理员')//这里不知道这里外部逻辑,async实际返回也是promise,直接throw 错误抛给外部获取 throw 'business-error-不是管理员' } console.log('运行到这了') // ... 继续在这向后端 axios // teamDetails.value = true // groupStore.value = e return '执行成功返回值' } catch (ex) {//getGroupRole中Promise中如果reject用catch获取 console.log('business-error', ex) throw 'getGroupRole执行失败'; } } async function myBusiness(e) { try { let result = await business(e); console.log('success',result) } catch (ex) { console.log('error',ex) } } myBusiness({ id: 111 }) </script>本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报