C语言通讯录printf问题，为什么name和home是int型变量？

Question

typedef struct addressbook
{
    char name[12];
    int tel[12];
    int email[12];
     char home[12];
}mess;
#include<stdio.h>
void showAll(mess *p,int n)
{   printf("%s\t%s\t%s\t%s\n","name","tel","email","home");
     int i;
    for(i=0;i<n;i++)
    {    
        printf("%s\t%d\t%d\t%s\n",*(p+i)->name,*(p+i)->tel,*(p+i)->email,*(p+i)->home);
    }
}

```c
[Error] format '%s' expects argument of type 'char *', but argument 2 has type 'int' [-Werror=format=]
[Error] format '%s' expects argument of type 'char *', but argument 5 has type 'int' [-Werror=format=]

Answer 1

修改如下，改动处见注释，供参考：

#include<stdio.h>
#include<string.h>
typedef struct addressbook
{
    char name[12];
    int  tel;        //[12];修改
    int  email;      //[12];修改
    char home[12];
}mess;

void showAll(mess *p,int n)
{
    printf("%s\t%s\t%s\t%s\n","name","tel","email","home");
    int i;
    for(i=0;i<n;i++)
    {
        printf("%s\t%d\t%d\t%s\n",(p+i)->name,(p+i)->tel,(p+i)->email,(p+i)->home); //修改
        //printf("%s\t%d\t%d\t%s\n",*(p+i)->name,*(p+i)->tel,*(p+i)->email,*(p+i)->home);
    }
}