如何从foreach（）结果中删除最后的结果

Question

I have some PHP code that grabs data from JSON. The code retruns all the usernames, including the current username to display. My question is, how would I only allow it so that it only shows the recent usernames and not the current?

I am using the Minecraft API for this and the JSON code I am getting can be found here.

Note that _scrunch is the current username.

Here's my code that displays the names:

// Save the uuid
$uuid = $json->id;

// Get the history (using $json->uuid)
$content = file_get_contents('https://api.mojang.com/user/profiles/' . urlencode($uuid) . '/names');

// Decode it
$json = json_decode($content);

$names = array(); // Create a new array

foreach ($json as $name) {
    $input = $name->name;

    if (!empty($name->changedToAt)) {
        // Convert to YYYY-MM-DD HH:MM:SS format
        //do

       // $input .= ' (changed at ' . $time . ')';
    }

    $names[] = $input; // Add each "name" value to our array "names"

}

and to display it

<?php echo implode(', ', $names) ;?>

Any help would be great! Thanks!

Answer 1

In your loop, just check and exclude if it's the user's name:

foreach ($json as $name) {
    $input = $name->name;
    if ($input != _scrunch) {

        if (!empty($name->changedToAt)) {
            // Convert to YYYY-MM-DD HH:MM:SS format
            //do

           // $input .= ' (changed at ' . $time . ')';
        }

        $names[] = $input; // Add each "name" value to our array "names"

    }
}