关于#c++#的问题：请教一下为什么用静态create方法返回智能指针，三个地址不同的智能指针，打印该类成员值相同，代码如下：#include <iostream>

Question

请教一下为什么用静态create方法返回智能指针，三个地址不同的智能指针，打印该类成员值相同，代码如下：

#include <iostream>
#include  <memory> 
using namespace std;

class Generator
{
public:
    typedef shared_ptr<Generator> Pointer;
    static Pointer create() {return (Pointer)(new Generator()) ;}    
    int getData() const {return mdata;}
    void setData(int data) {mdata = data;}
    ~Generator();
private:
    Generator();
    int mdata;
};

Generator::Generator():mdata(1)
{
    // cout<<"construct Generator \n"<<endl;
}

Generator::~Generator()
{
    // cout<<"destruct Generator \n"<<endl;
}

int main()
{
    Generator::Pointer pGenerator = Generator::create();
    cout<<pGenerator->getData()<<endl;//打印  1
    pGenerator->setData(100);//修改值为100
    cout<<pGenerator->getData()<<endl;//打印  100

    Generator::Pointer pGenerator1 = Generator::create();
    cout<<pGenerator->getData()<<endl;//打印  100
    
    Generator::Pointer pGenerator2(Generator::create());
    cout<<pGenerator->getData()<<endl;//打印  100
    
    cout<<pGenerator<<endl<<pGenerator1<<endl<<pGenerator2<<endl;//0x20bb090 0x20bb0d0 0x20bb110
}

Answer 1

你下面调用的还是pGenerator而不是pGenerator1